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Use left arrow to place cursor after the last 'o'.
Push backspace so the command now reads println("fo")
Push return.
Command changes to println("foo") and foo is printed out instead of fo.
This affects numbers as well e.g.
Load Ammonite REPL
Type println(100).
Push return.
100 is printed out as expected.
Push up arrow to show last command.
Use left arrow to place cursor after the last '0'.
Push backspace so the command now reads println(10)
Push return.
Command changes to println(100) and 100 is printed out instead of 10.
Notes
This issue specifically affects modifying previous statement as described in steps. Entering println("foo") followed by manually typing println("fo") works as expected.
This issue specifically affects subsequences of the string/number, so changing foo to bar or 100 to 200 will behave as expected.
The text was updated successfully, but these errors were encountered:
System
Steps to reproduce
println("foo")
.foo
is printed out as expected.println("fo")
println("foo")
andfoo
is printed out instead offo
.This affects numbers as well e.g.
println(100)
.100
is printed out as expected.println(10)
println(100)
and100
is printed out instead of10
.Notes
println("foo")
followed by manually typingprintln("fo")
works as expected.foo
tobar
or100
to200
will behave as expected.The text was updated successfully, but these errors were encountered: