Caching for cython.inline() does not differentiate between different compiler configurations.

[will-ca]

>>> cython.inline('def f(int a, int b):\n\treturn a/b\nreturn f', language_level=3)(5,2)
2.5

>>> cython.inline('def f(int a, int b):\n\treturn a/b\nreturn f', language_level=2)(5,2)
2
>>> cython.inline('def f(int a, int b):\n\treturn a/b\nreturn f', language_level=3)(5,2)
2

[scoder]

Interesting. I had added the language_level to the module hash, but it seems to have no effect.

cython/Cython/Build/Inline.py

Lines 193 to 194 in 0b81c76

	key = orig_code, arg_sigs, sys.version_info, sys.executable, language_level, Cython.__version__
	module_name = "_cython_inline_" + hashlib.sha1(_unicode(key).encode('utf-8')).hexdigest()

[will-ca]

I think that hash is being skipped entirely by the fast path at the very start of the function, which only takes into account the code string and (unbound?) argument signature:

cython/Cython/Build/Inline.py

Lines 153 to 162 in 0b81c76

	# Fast path if this has been called in this session.
	_unbound_symbols = _cython_inline_cache.get(code)
	if _unbound_symbols is not None:
	_populate_unbound(kwds, _unbound_symbols, locals, globals)
	args = sorted(kwds.items())
	arg_sigs = tuple([(get_type(value, ctx), arg) for arg, value in args])
	invoke = _cython_inline_cache.get((code, arg_sigs))
	if invoke is not None:
	arg_list = [arg[1] for arg in args]
	return invoke(*arg_list)