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Fixed #15208 - Document ModelAdmin.formfield_for_choice_field; thanks…

… julien.

git-svn-id: bcc190cf-cafb-0310-a4f2-bffc1f526a37
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commit f77d81de3d08c3e441b2fdd168af51a141267493 1 parent a9ebf9e
Tim Graham timgraham authored
Showing with 19 additions and 0 deletions.
  1. +19 −0 docs/ref/contrib/admin/index.txt
19 docs/ref/contrib/admin/index.txt
@@ -927,6 +927,25 @@ templates used by the :class:`ModelAdmin` views:
kwargs["queryset"] = Car.objects.filter(owner=request.user)
return super(MyModelAdmin, self).formfield_for_manytomany(db_field, request, **kwargs)
+.. method:: ModelAdmin.formfield_for_choice_field(self, db_field, request, **kwargs)
+ Like the ``formfield_for_foreignkey`` and ``formfield_for_manytomany``
+ methods, the ``formfield_for_choice_field`` method can be overridden to
+ change the default formfield for a field that has declared choices. For
+ example, if the choices available to a superuser should be different than
+ those available to regular staff, you could proceed as follows::
+ class MyModelAdmin(admin.ModelAdmin):
+ def formfield_for_choice_field(self, db_field, request, **kwargs):
+ if == "status":
+ kwargs['choices'] = (
+ ('accepted', 'Accepted'),
+ ('denied', 'Denied'),
+ )
+ if request.user.is_superuser:
+ kwargs['choices'] += (('ready', 'Ready for deployment'),)
+ return super(MyModelAdmin, self).formfield_for_choice_field(db_field, request, **kwargs)
.. method:: ModelAdmin.has_add_permission(self, request)
Should return ``True`` if adding an object is permitted, ``False``
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