templatized method shadowed by non-templatized in parameterless eponymous template

[dlangBugzillaToGithub]

monarchdodra reported this on 2013-12-10T02:52:55Z

Transferred from https://issues.dlang.org/show_bug.cgi?id=11715

Description

//----
template bar(T)
{
    void bar(){}        //Non template
    void bar(U)(U u){}  //Template
}

template foo1()
{
    void foo1()(){}     //Template
    void foo1(U)(U u){} //Template
}

template foo2()
{
    void foo2(){}       //Non template
    void foo2(U)(U u){} //Template
}

void main()
{
  bar!int();  //OK
  bar!int(1); //OK
  foo1();     //OK
  foo1(1);    //OK
  foo2();     //OK
  foo2(1);    //NOPE!
}
//----

Results in:

//----
Error: template main.foo2 does not match any function template declaration. Candidates are:
       main.foo2()()
Error: template main.foo2()() cannot deduce template function from argument types !()(int)
//----

I think this is not correct behavior. "bar" and "foo2" should have the same behavior. It *seems* like the compiler does not "see" foo2().foo2(U)(U u)

The workaround (as seen in foo1), is to make the non-template function a parameter-less template.