iota() should be statically specialized for increment 1

[dlangBugzillaToGithub]

andrei (@andralex) reported this on 2013-09-20T12:33:24Z

Transfered from https://issues.dlang.org/show_bug.cgi?id=11077

CC List

• iamthewilsonator

Description

iota() for integrals stores the step as a member variable. This makes the frequent case step=1 slower than it should. Calls using iota(max) or iota(min, max) should return a structure not storing step, and using ++ to get to the next item.

[dlangBugzillaToGithub]

iamthewilsonator commented on 2019-11-03T05:47:02Z

This is a phobos bug.