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std.regex.splitter generates spurious empty elements with empty delimiter #9997
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dmitry.olsh (@DmitryOlshansky) commented on 2013-12-18T13:10:33Z(In reply to comment #0)
> CODE:
> --------
> void main() {
> import std.string, std.stdio, std.regex;
> string s = "test";
> writeln(std.regex.splitter(s.toUpper, regex("")));
> }
> --------
>
> Output:
> --------
> ["", "T", "E", "S", "T", ""]
> --------
>
> The first and last empty elements should not be included in the result. Cf.
> Perl's split(//, "test").
The matter is more or less trivial, the only problem is what you actually want me to do?
No matter how I read this passage:
http://perldoc.perl.org/functions/split.html
I can only gather that 0-width match at front of input is never produced (okay..). What the heck must be happening with the one at the end isn't clear to me at all.
Given that the following test produces ["T", "E", "S", "T"] we may just ignore 0-width match at both ends to be in line. The behaviour needs to be documented though. Anyway - seems good?
void main() {
import std.string, std.algorithm, std.stdio;//, std.regex;
string s = "test";
writeln(splitter(s.toUpper, ""));
} |
hsteoh commented on 2013-12-18T14:28:29Z$ perl -e'print join(":", split(//, "test")), "\n";'
t:e:s:t
$
So yes, I expect std.regex.splitter to return ["t", "e", "s", "t"] when the delimiter is empty. |
dmitry.olsh (@DmitryOlshansky) commented on 2013-12-19T08:51:38Z(In reply to comment #2)
> $ perl -e'print join(":", split(//, "test")), "\n";'
> t:e:s:t
> $
>
>
> So yes, I expect std.regex.splitter to return ["t", "e", "s", "t"] when the
> delimiter is empty.
But then there is this:
perl -e'print join(":", split(/, /, ", test, ")), "\n";'
:test
That makes no sense to me whatsoever.
We have tests already (always had, even before 2.056) that state the opposite.
In fact they make sure that both zero-width pieces are found (at start and at end). |
dmitry.olsh (@DmitryOlshansky) commented on 2013-12-19T10:11:20Zhttps://github.com/D-Programming-Language/phobos/pull/1790
My compromise is to follow std.algorithm splitter and special case 0-width matches as if 0-width needles. |
monarchdodra commented on 2013-12-19T10:18:12ZArguably, 0-width splitting makes no sense: If it were to rigorously follow the rules, then you'd simply end up with an infinite amount of leading tokens.
["", "T", "E", "S", "T", ""]
Makes no sense to me. Why is there an empty leading/trailing token, but none between each letter?
This means that in regards to 0-length splitting, it should either be an *error*, or have a *special behavior*
std.algorithm.split simply special cases to do what seems most useful (what is documented by pearl, AFAIK). I think having regex do the same is most sensible. |
monarchdodra commented on 2013-12-19T10:22:46Z(In reply to comment #5)
> Arguably, 0-width splitting makes no sense: If it were to rigorously follow the
> rules, then you'd simply end up with an infinite amount of leading tokens.
> ["", "T", "E", "S", "T", ""]
> Makes no sense to me. Why is there an empty leading/trailing token, but none
> between each letter?
>
> This means that in regards to 0-length splitting, it should either be an
> *error*, or have a *special behavior*
>
> std.algorithm.split simply special cases to do what seems most useful (what is
> documented by pearl, AFAIK). I think having regex do the same is most sensible.
Hum... Actually, now that I think about it, algorithm splitter works on constant length separator. I'm not sure how you'd handle a separator that may and or may not be empty...
See the examples in your pull. |
dmitry.olsh (@DmitryOlshansky) commented on 2013-12-19T10:48:49Z(In reply to comment #5)
> Arguably, 0-width splitting makes no sense: If it were to rigorously follow the
> rules, then you'd simply end up with an infinite amount of leading tokens.
> ["", "T", "E", "S", "T", ""]
> Makes no sense to me. Why is there an empty leading/trailing token, but none
> between each letter?
>
> This means that in regards to 0-length splitting, it should either be an
> *error*, or have a *special behavior*
There is already special case that 0-width regular expression match advances input by one codepoint. It's exactly this special case that produces the string above, nothing to worry about.
>
> std.algorithm.split simply special cases to do what seems most useful (what is
> documented by pearl, AFAIK). I think having regex do the same is most sensible.
Doing special-special case is kind of bad. The more I look at this the more it's clear to me that we either have to decipher Perl's behaviour or give up. |
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hsteoh reported this on 2013-08-07T12:54:11Z
Transfered from https://issues.dlang.org/show_bug.cgi?id=10772
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