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#lang typed/racket/base/no-check
(require racket/list)
(provide list-union list-difference list-intersection unique/eq? unique/equal?)
(: list-union ((Listof Symbol) (Listof Symbol) -> (Listof Symbol)))
(define (list-union s1 s2)
(cond [(null? s1) s2]
[(memq (car s1) s2)
(list-union (cdr s1) s2)]
[else (cons (car s1) (list-union (cdr s1) s2))]))
(: list-difference ((Listof Symbol) (Listof Symbol) -> (Listof Symbol)))
(define (list-difference s1 s2)
(cond [(null? s1) '()]
[(memq (car s1) s2)
(list-difference (cdr s1) s2)]
[else
(cons (car s1) (list-difference (cdr s1) s2))]))
(: list-intersection ((Listof Symbol) (Listof Symbol) -> (Listof Symbol)))
(define (list-intersection s1 s2)
(cond [(null? s1) '()]
[(memq (car s1) s2)
(cons (car s1) (list-intersection (cdr s1) s2))]
[else
(list-intersection (cdr s1) s2)]))
;; Trying to work around what looks like a bug in typed racket:
(define string-sort (inst sort String String))
(: unique/eq? ((Listof Symbol) -> (Listof Symbol)))
(define (unique/eq? los)
(let: ([ht : (HashTable Symbol Boolean) (make-hasheq)])
(for ([l los])
(hash-set! ht l #t))
(map string->symbol
(string-sort
(hash-map ht (lambda: ([k : Symbol] [v : Boolean])
(symbol->string k)))
string<?))))
(: unique/equal? (All (A) ((Listof A) -> (Listof A))))
(define (unique/equal? lst)
(cond
[(empty? lst)
empty]
[(member (first lst) (rest lst))
(unique/equal? (rest lst))]
[else
(cons (first lst)
(unique/equal? (rest lst)))]))
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