Browse files

usage.c: detect recursion in die routines and bail out immediately

It is theoretically possible for a die handler to get into a state of
infinite recursion.  For example, if a die handler called another function
which itself called die().  Let's at least detect this situation, inform the
user, and call exit.

Signed-off-by: Brandon Casey <bcasey@nvidia.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
  • Loading branch information...
1 parent 7e20105 commit cd163d4b4e190d5e5131962c1b8f84601d4736d4 @drafnel drafnel committed with gitster Nov 14, 2012
Showing with 15 additions and 0 deletions.
  1. +15 −0 usage.c
View
15 usage.c
@@ -6,6 +6,8 @@
#include "git-compat-util.h"
#include "cache.h"
+static int dying;
+
void vreportf(const char *prefix, const char *err, va_list params)
{
char msg[4096];
@@ -82,6 +84,12 @@ void NORETURN die(const char *err, ...)
{
va_list params;
+ if (dying) {
+ fputs("fatal: recursion detected in die handler\n", stderr);
+ exit(128);
+ }
+ dying = 1;
+
va_start(params, err);
die_routine(err, params);
va_end(params);
@@ -94,6 +102,13 @@ void NORETURN die_errno(const char *fmt, ...)
char str_error[256], *err;
int i, j;
+ if (dying) {
+ fputs("fatal: recursion detected in die_errno handler\n",
+ stderr);
+ exit(128);
+ }
+ dying = 1;
+
err = strerror(errno);
for (i = j = 0; err[i] && j < sizeof(str_error) - 1; ) {
if ((str_error[j++] = err[i++]) != '%')

0 comments on commit cd163d4

Please sign in to comment.