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bzip2: improve performance
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Improve performance of move-to-front by using cache-friendly
copies instead of doubly-linked list. Simplify so that the
underlying slice is the object. Remove the n=0 special case,
      which was actually slower with the copy approach.

benchmark                 old ns/op     new ns/op     delta
BenchmarkDecodeDigits     26429714      23859699      -9.72%
BenchmarkDecodeTwain      76684510      67591946      -11.86%

benchmark                 old MB/s     new MB/s     speedup
BenchmarkDecodeDigits     1.63         1.81         1.11x
BenchmarkDecodeTwain      1.63         1.85         1.13x

Updates #6754.

LGTM=adg, agl, josharian
R=adg, agl, josharian
CC=golang-codereviews
https://golang.org/cl/131840043
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jeffallen authored and agl committed Aug 18, 2014
1 parent 523aa93 commit 6d248ce
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Showing 2 changed files with 55 additions and 62 deletions.
38 changes: 38 additions & 0 deletions src/pkg/compress/bzip2/bzip2_test.go
Original file line number Diff line number Diff line change
Expand Up @@ -216,6 +216,44 @@ func TestOutOfRangeSelector(t *testing.T) {
ioutil.ReadAll(decompressor)
}

func TestMTF(t *testing.T) {
mtf := newMTFDecoderWithRange(5)

// 0 1 2 3 4
expect := byte(1)
x := mtf.Decode(1)
if x != expect {
t.Errorf("expected %v, got %v", expect, x)
}

// 1 0 2 3 4
x = mtf.Decode(0)
if x != expect {
t.Errorf("expected %v, got %v", expect, x)
}

// 1 0 2 3 4
expect = byte(0)
x = mtf.Decode(1)
if x != expect {
t.Errorf("expected %v, got %v", expect, x)
}

// 0 1 2 3 4
expect = byte(4)
x = mtf.Decode(4)
if x != expect {
t.Errorf("expected %v, got %v", expect, x)
}

// 4 0 1 2 3
expect = byte(0)
x = mtf.Decode(1)
if x != expect {
t.Errorf("expected %v, got %v", expect, x)
}
}

var bufferOverrunBase64 string = `
QlpoNTFBWSZTWTzyiGcACMP/////////////////////////////////3/7f3///
////4N/fCZODak2Xo44GIHZgkGzDRbFAuwAAKoFV7T6AO6qwA6APb6s2rOoAkAAD
Expand Down
79 changes: 17 additions & 62 deletions src/pkg/compress/bzip2/move_to_front.go
Original file line number Diff line number Diff line change
Expand Up @@ -11,88 +11,43 @@ package bzip2
// index into that list. When a symbol is referenced, it's moved to the front
// of the list. Thus, a repeated symbol ends up being encoded with many zeros,
// as the symbol will be at the front of the list after the first access.
type moveToFrontDecoder struct {
// Rather than actually keep the list in memory, the symbols are stored
// as a circular, double linked list with the symbol indexed by head
// at the front of the list.
symbols [256]byte
next [256]uint8
prev [256]uint8
head uint8
len int
}
type moveToFrontDecoder []byte

// newMTFDecoder creates a move-to-front decoder with an explicit initial list
// of symbols.
func newMTFDecoder(symbols []byte) *moveToFrontDecoder {
func newMTFDecoder(symbols []byte) moveToFrontDecoder {
if len(symbols) > 256 {
panic("too many symbols")
}

m := new(moveToFrontDecoder)
copy(m.symbols[:], symbols)
m.len = len(symbols)
m.threadLinkedList()
return m
return moveToFrontDecoder(symbols)
}

// newMTFDecoderWithRange creates a move-to-front decoder with an initial
// symbol list of 0...n-1.
func newMTFDecoderWithRange(n int) *moveToFrontDecoder {
func newMTFDecoderWithRange(n int) moveToFrontDecoder {
if n > 256 {
panic("newMTFDecoderWithRange: cannot have > 256 symbols")
}

m := new(moveToFrontDecoder)
m := make([]byte, n)
for i := 0; i < n; i++ {
m.symbols[byte(i)] = byte(i)
}
m.len = n
m.threadLinkedList()
return m
}

// threadLinkedList creates the initial linked-list pointers.
func (m *moveToFrontDecoder) threadLinkedList() {
if m.len == 0 {
return
}

m.prev[0] = uint8(m.len - 1)

for i := byte(0); int(i) < m.len-1; i++ {
m.next[i] = uint8(i + 1)
m.prev[i+1] = uint8(i)
m[i] = byte(i)
}

m.next[m.len-1] = 0
return moveToFrontDecoder(m)
}

func (m *moveToFrontDecoder) Decode(n int) (b byte) {
// Most of the time, n will be zero so it's worth dealing with this
// simple case.
if n == 0 {
return m.symbols[m.head]
}

i := m.head
for j := 0; j < n; j++ {
i = m.next[i]
}
b = m.symbols[i]

m.next[m.prev[i]] = m.next[i]
m.prev[m.next[i]] = m.prev[i]
m.next[i] = m.head
m.prev[i] = m.prev[m.head]
m.next[m.prev[m.head]] = i
m.prev[m.head] = i
m.head = i

func (m moveToFrontDecoder) Decode(n int) (b byte) {
// Implement move-to-front with a simple copy. This approach
// beats more sophisticated approaches in benchmarking, probably
// because it has high locality of reference inside of a
// single cache line (most move-to-front operations have n < 64).
b = m[n]
copy(m[1:], m[:n])
m[0] = b
return
}

// First returns the symbol at the front of the list.
func (m *moveToFrontDecoder) First() byte {
return m.symbols[m.head]
func (m moveToFrontDecoder) First() byte {
return m[0]
}

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