os/signal: Unable to catch SIGHUP signal multiple times

I have the following code:

func HandleSIGHUP() chan os.Signal {
    sig := make(chan os.Signal, 1)

    signal.Notify(sig, syscall.SIGHUP)

    return sig
}

I "register" the signal like so:

go func() {
    for {
        <-HandleSIGHUP()

        // do something
    }
}()

The problem that I'm experiencing is that I'm only able to catch one SIGHUP. For example if I send multiple kill -SIGHUP <pid> to the process, the "register" code only runs once. How can I get it to run every time the signal is sent?

$ go version
go version go1.4.2 linux/amd64

I also posted this here: http://stackoverflow.com/questions/31395761/handle-signal-multiple-times-in-golang

[ianlancetaylor]

It's sort of peculiar that each time through the loop you are creating and registering a new channel. Is that really what you want to do? Why not create just one channel, before the loop?

@ianlancetaylor I tried many ways but they all have the same result; the code above is my last latest try.

[ianlancetaylor]

I can't recreate the problem.

I ran this: http://play.golang.org/p/7FAc7wzuhK . In a separate terminal window, I typed "kill -SIGHUP PID". Each time I ran that command, the program printed SIGHUP.

Please show us a complete program.

@ianlancetaylor
Indeed; unable to reproduce. I must have something else going on here.

It's working now. I probably tried to compile and didn't pay attention if the binary got updated (prob had syntax error somewhere with autobuild).