syscall: LoadDLL() bad error formatting on Windows

[ip]

This is a tiny issue. I use Windows 7 x64. How to reproduce:
echo > corrupted.dll
Create main.go:

package main

import (
    "syscall"
    "fmt"
)

func main() {
    _, err := syscall.LoadDLL("./corrupted.dll")
    if err != nil {
        fmt.Println(err)
    }
}

It writes: Failed to load ./corrupted.dll: %1 is not a valid Win32 application.

Probably there are more similar errors in other places.

[alexbrainman]

Windows returns you ERROR_BAD_EXE_FORMAT. The error message for it (https://msdn.microsoft.com/en-us/library/windows/desktop/ms681382(v=vs.85).aspx) is "%1 is not a valid Win32 application.". So that is what Go prints.

It is unfortunate, but I don't see how we can improve this situation.

Alex

[ip]

Yes, sorry, I just wrote same program in C++ and got same output.