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strings.TrimRight() has bug when trim some strings #14657

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awkr opened this Issue Mar 5, 2016 · 3 comments

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@awkr

awkr commented Mar 5, 2016

Please answer these questions before submitting your issue. Thanks!

  1. What version of Go are you using (go version)?

go1.6 darwin/amd64

  1. What operating system and processor architecture are you using (go env)?

darwin/amd64

  1. What did you do?
    (Use play.golang.org to provide a runnable example, if possible.)

package main

import (
"fmt"
"path/filepath"
"strings"
)

func main() {
path := "Order.thrift"

b := filepath.Base(path)
fmt.Println(b) // Order.thrift

e := filepath.Ext(path)
fmt.Println(e) // .thrift

n := strings.TrimRight(b, e)
fmt.Println(n)

}

  1. What did you expect to see?

Order

  1. What did you see instead?

Orde

@davecheney

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davecheney commented Mar 5, 2016

Trimright removes characters in the set e from b, starting from the right. It's not what you want.

You want, n := b[:len(b)-len(e)]

As you know that e is the suffix of b

On 5 Mar 2016, at 20:15, Hongjian Zhu notifications@github.com wrote:

Please answer these questions before submitting your issue. Thanks!

What version of Go are you using (go version)?
go1.6 darwin/amd64

What operating system and processor architecture are you using (go env)?
darwin/amd64

What did you do? (Use play.golang.org to provide a runnable example, if possible.)
package main

import (
"fmt"
"path/filepath"
"strings"
)

func main() {
path := "Order.thrift"

b := filepath.Base(path)
fmt.Println(b) // Order.thrift

e := filepath.Ext(path)
fmt.Println(e) // .thrift

n := strings.TrimRight(b, e)
fmt.Println(n)
}

What did you expect to see?
Order

What did you see instead?
Orde


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@minux minux closed this Mar 5, 2016

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minux commented Mar 5, 2016

@awkr

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awkr commented Mar 5, 2016

@davecheney, @minux thank you guys for your kindly replay :-]

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