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encoding/xml: Unmarshal can't resolve recursive list sample #3088

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dlintw opened this Issue Feb 21, 2012 · 3 comments

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dlintw commented Feb 21, 2012

What steps will reproduce the problem?
1. capture the code in this description to xml_parse.go
2. go run xml_parse.go

What is the expected output?
a::b::c::nil

What do you see instead?
 :: nil

Which compiler are you using (5g, 6g, 8g, gccgo)?
go

Which operating system are you using?
archlinux x86_64

Which revision are you using?  (hg identify)
58bc8aae4abb

Please provide any additional information below.

// sample from http://research.swtch.com/godata2
package main

import (
    "encoding/xml"
    "fmt"
    "log"
)

var encoded = `
   <list><value>a</value>
       <list><value>b</value>
           <list><value>c</value>
           </list>
       </list>
   </list>
`

type List struct {
    Value string
    List  *List
}

func (l *List) String() string {
    if l == nil {
        return "nil"
    }
    return l.Value + " :: " + l.List.String()
}

func main() {
    var l *List
    err := xml.Unmarshal([]byte(encoded),&l)
    if err != nil {
        log.Fatalln("xml.Unmarshal: ", err)
    }
    fmt.Println(l)
}
@dlintw

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dlintw commented Feb 21, 2012

Comment 1:

Sorry, this is my fault. I should change the <list> into <List>
But, I still don't know how to extract xml with lowercase element.
If possible, could you explain a example on http://localhost:6060/doc/go1.html
Or, better on http://localhost:6060/pkg/encoding/xml
@dlintw

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dlintw commented Feb 21, 2012

Comment 2:

Here is my modified code, it works.
I think this issue could closed.
// sample from http://research.swtch.com/godata2
package main
import (
    "encoding/xml"
    "fmt"
    "log"
)
var encoded = `
   <List><value>a</value>
       <List><value>b</value>
           <List><value>c</value>
           </List>
       </List>
   </List>
`
type List struct {
    Value string `xml:"value"`
    List  *List
}
func (l *List) String() string {
    if l == nil {
        return "nil"
    }
    return l.Value + " :: " + l.List.String()
}
func main() {
    var l *List
    err := xml.Unmarshal([]byte(encoded),&l)
    if err != nil {
        log.Fatalln("xml.Unmarshal: ", err)
    }
    fmt.Println(l)
}
@dsymonds

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dsymonds commented Feb 21, 2012

Comment 3:

Status changed to WorkingAsIntended.

@mikioh mikioh changed the title xml.Unmarshal can't resolve recursive list sample encoding/xml: Unmarshal can't resolve recursive list sample Jan 9, 2015

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