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What version of Go are you using (go version)?
$ go version go version go1.13rc2 linux/amd64
Does this issue reproduce with the latest release?
yes
What operating system and processor architecture are you using (go env)?
go env Output
$ go env GO111MODULE="" GOARCH="amd64" GOBIN="" GOCACHE="/home/mischief/.cache/go-build" GOENV="/home/mischief/.config/go/env" GOEXE="" GOFLAGS="" GOHOSTARCH="amd64" GOHOSTOS="linux" GONOPROXY="" GONOSUMDB="" GOOS="linux" GOPATH="/home/mischief/code/go" GOPRIVATE="" GOPROXY="https://proxy.golang.org,direct" GOROOT="/home/mischief/src/go" GOSUMDB="sum.golang.org" GOTMPDIR="" GOTOOLDIR="/home/mischief/src/go/pkg/tool/linux_amd64" GCCGO="gccgo" AR="ar" CC="gcc" CXX="g++" CGO_ENABLED="1" GOMOD="" CGO_CFLAGS="-g -O2" CGO_CPPFLAGS="" CGO_CXXFLAGS="-g -O2" CGO_FFLAGS="-g -O2" CGO_LDFLAGS="-g -O2" PKG_CONFIG="pkg-config" GOGCCFLAGS="-fPIC -m64 -pthread -fmessage-length=0 -fdebug-prefix-map=/tmp/go-build480716661=/tmp/go-build -gno-record-gcc-switches"
What did you do?
package main
import (
"fmt"
"golang.org/x/sys/unix"
)
func main() {
seq := unix.TIPCServiceRange{
Type: 999,
Lower: 0,
Upper: ^uint32(0),
}
sub := &unix.TIPCSubscr{
Seq: seq,
Timeout: unix.TIPC_WAIT_FOREVER,
Filter: unix.TIPC_SUB_PORTS,
}
fmt.Println(sub)
}What did you expect to see?
the subscription is printed.
What did you see instead?
./f.go:17:3: constant -1 overflows uint32
TIPC_WAIT_FOREVER is a sentinel value to make a subscription never time out (see here).
its value is currently const TIPC_WAIT_FOREVER = -0x1. the kernel headers define it as a macro ((~0)). however, the TIPCSubscr.Timeout field is a uint32, so assignment doesn't work.
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