runtime: can preempt running G asynchronously by sending sigurg while asyncpreemptoff is set

[koushki]

What version of Go are you using (go version)?

$ go version
go1.14.2 linux/amd64

Does this issue reproduce with the latest release?

Yes

What operating system and processor architecture are you using (go env)?

go env Output

GO111MODULE=""
GOARCH="amd64"
GOBIN=""
GOCACHE="/root/.cache/go-build"
GOENV="/root/.config/go/env"
GOEXE=""
GOFLAGS=""
GOHOSTARCH="amd64"
GOHOSTOS="linux"
GOINSECURE=""
GONOPROXY=""
GONOSUMDB=""
GOOS="linux"
GOPATH="/go"
GOPRIVATE=""
GOPROXY="https://proxy.golang.org,direct"
GOROOT="/usr/local/go"
GOSUMDB="sum.golang.org"
GOTMPDIR=""
GOTOOLDIR="/usr/local/go/pkg/tool/linux_amd64"
GCCGO="gccgo"
AR="ar"
CC="gcc"
CXX="g++"
CGO_ENABLED="1"
GOMOD=""
CGO_CFLAGS="-g -O2"
CGO_CPPFLAGS=""
CGO_CXXFLAGS="-g -O2"
CGO_FFLAGS="-g -O2"
CGO_LDFLAGS="-g -O2"
PKG_CONFIG="pkg-config"
GOGCCFLAGS="-fPIC -m64 -pthread -fmessage-length=0 -fdebug-prefix-map=/tmp/go-build332853226=/tmp/go-build -gno-record-gcc-switches"

What did you do?

While using GODEBUG=asyncpreemptoff=1 if you send a sigurg sig to a thread, the scheduler will preempt the running G.

package main

import (
	"fmt"
	"runtime"
	"time"
	"golang.org/x/sys/unix"
)

func main() {
	runtime.GOMAXPROCS(1)
	go func() {
		fmt.Printf("tid %d\n", unix.Gettid())
		for {
		}
	}()
	time.Sleep(time.Second)
	fmt.Println("Done!")
}

then run it with asyncpreemptoff

GODEBUG=asyncpreemptoff=1 go run main.go
tid 2782

now use the tid to send the sig

kill -s sigurg 2782

What did you expect to see?

Since we use asyncpreemptoff=1 i expect the app shouldn't be finished!

What did you see instead?

the program prints Done!