From 85ee08b9a621e60df60b2c009a1c9f69059209b7 Mon Sep 17 00:00:00 2001
From: Antim Pal <134076504+iamAntimPal@users.noreply.github.com>
Date: Sat, 22 Mar 2025 02:03:09 +0530
Subject: [PATCH 1/2] 1164. Product Price at a Given Date

Co-Authored-By: Antim-IWP <203163676+Antim-IWP@users.noreply.github.com>
---
 .../1164. Product Price at a Given Date.sql   | 46 +++++++++++++++++++
 .../180. Consecutive Numbers.sql              |  2 +-
 2 files changed, 47 insertions(+), 1 deletion(-)
 create mode 100644 LeetCode SQL 50 Solution/1164. Product Price at a Given Date.sql

diff --git a/LeetCode SQL 50 Solution/1164. Product Price at a Given Date.sql b/LeetCode SQL 50 Solution/1164. Product Price at a Given Date.sql
new file mode 100644
index 0000000..6fa8bd6
--- /dev/null
+++ b/LeetCode SQL 50 Solution/1164. Product Price at a Given Date.sql	
@@ -0,0 +1,46 @@
+
+1164. Product Price at a Given Date
+
+Table: Products
+
++---------------+---------+
+| Column Name   | Type    |
++---------------+---------+
+| product_id    | int     |
+| new_price     | int     |
+| change_date   | date    |
++---------------+---------+
+(product_id, change_date) is the primary key (combination of columns with unique values) of this table.
+Each row of this table indicates that the price of some product was changed to a new price at some date.
+ 
+
+Write a solution to find the prices of all products on 2019-08-16. Assume the price of all products before any change is 10.
+
+Return the result table in any order.
+
+The result format is in the following example.
+
+ 
+
+Example 1:
+
+Input: 
+Products table:
++------------+-----------+-------------+
+| product_id | new_price | change_date |
++------------+-----------+-------------+
+| 1          | 20        | 2019-08-14  |
+| 2          | 50        | 2019-08-14  |
+| 1          | 30        | 2019-08-15  |
+| 1          | 35        | 2019-08-16  |
+| 2          | 65        | 2019-08-17  |
+| 3          | 20        | 2019-08-18  |
++------------+-----------+-------------+
+Output: 
++------------+-------+
+| product_id | price |
++------------+-------+
+| 2          | 50    |
+| 1          | 35    |
+| 3          | 10    |
++------------+-------+
\ No newline at end of file
diff --git a/LeetCode SQL 50 Solution/180. Consecutive Numbers.sql b/LeetCode SQL 50 Solution/180. Consecutive Numbers.sql
index 04a0b6c..2ef1d2c 100644
--- a/LeetCode SQL 50 Solution/180. Consecutive Numbers.sql	
+++ b/LeetCode SQL 50 Solution/180. Consecutive Numbers.sql	
@@ -109,4 +109,4 @@ It then filters out rows where the current value is the same as both the previou
 
 Final Output:
 The final result is a list of distinct numbers that appear consecutively in the Logs table.
-"""
\ No newline at end of file
+"""

From d5abc631b27eb46c1548a16e8253b413bf860b1e Mon Sep 17 00:00:00 2001
From: Antim Pal <134076504+iamAntimPal@users.noreply.github.com>
Date: Sat, 22 Mar 2025 02:03:30 +0530
Subject: [PATCH 2/2] Update 180. Consecutive Numbers.sql

Co-Authored-By: Antim-IWP <203163676+Antim-IWP@users.noreply.github.com>
---
 .../180. Consecutive Numbers.sql              | 21 +++++++++++++++++++
 1 file changed, 21 insertions(+)

diff --git a/LeetCode SQL 50 Solution/180. Consecutive Numbers.sql b/LeetCode SQL 50 Solution/180. Consecutive Numbers.sql
index 2ef1d2c..3a3943a 100644
--- a/LeetCode SQL 50 Solution/180. Consecutive Numbers.sql	
+++ b/LeetCode SQL 50 Solution/180. Consecutive Numbers.sql	
@@ -110,3 +110,24 @@ It then filters out rows where the current value is the same as both the previou
 Final Output:
 The final result is a list of distinct numbers that appear consecutively in the Logs table.
 """
+
+
+# Write your MySQL query statement below
+# Write your MySQL query statement below
+WITH
+    T AS (SELECT DISTINCT product_id FROM Products),
+    P AS (
+        SELECT product_id, new_price AS price
+        FROM Products
+        WHERE
+            (product_id, change_date) IN (
+                SELECT product_id, MAX(change_date) AS change_date
+                FROM Products
+                WHERE change_date <= '2019-08-16'
+                GROUP BY 1
+            )
+    )
+SELECT product_id, IFNULL(price, 10) AS price
+FROM
+    T
+    LEFT JOIN P USING (product_id);