DataGridView and Control

[itg-assistant]

Cristian Zerbinati asked 2018-04-10 11:02:59 UTC

Hi,

if I have set a datagriview as Virtualmode=true, and I add a column with checkbox, the checkbox do not receive click

is it normal?

Regards

Cristian

[itg-assistant]

Luca answered 2018-04-10 22:52:15 UTC

Cannot reproduce without a test case.

[itg-assistant]

Cristian Zerbinati answered 2018-04-11 08:11:42 UTC

Private Sub Window1_Load(sender As Object, e As EventArgs) Handles MyBase.Load
DataGridView1.VirtualMode = True
DataGridView1.RowCount = 10
'aggiungo la colonna col checkbox per la selezione
Dim col As New DataGridViewCheckBoxColumn With {
.Name = "ck",
.Width = "30",
.ReadOnly = False,
.Resizable = False,
.FillWeight = 10
}
Dim ck As New CheckBox
ck.Dock = DockStyle.Fill
DataGridView1.Columns.Insert(0, col)
End Sub

[itg-assistant]

Luca answered 2018-04-11 13:41:23 UTC

I can't understand what the code is expected to do. The checkbox is created and not shown or attached or assigned. Place it on a page or form and it will work. It's not related to the DataGridViewCheckBoxColumn.

The datagrid sets VirtualMode on but doesn't handle the data events. See https://docs.microsoft.com/en-us/dotnet/framework/winforms/controls/implementing-virtual-mode-wf-datagridview-control

[itg-assistant]

Cristian Zerbinati answered 2018-04-11 14:00:08 UTC

sorry if I did not explain well.

the checkbox that I have crate and place inside datagridview, are not checkable. is it normal, because it is in virtual mode?

[itg-assistant]

Luca answered 2018-04-11 14:03:25 UTC

You don’t need to create any checkbox inside the datagridview. The DataGridViewCheckBoxColumn renders the checkboxes by itself. They are checkable but since you turned on VirtualMode you have to store and retrieve the data. The alternative is to leave VirtualMode off. See CellValuePushed and CellValueNeeded and the tutorial I linked.

[itg-assistant]

Cristian Zerbinati answered 2018-04-11 14:09:57 UTC

damn you’re right!
sorry
thanks
Cristian