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# Thanks to Daenyth for help porting this to Arch Linux.
import os, platform, re, subprocess
_distributor_id_cmdline_re = re.compile("(?:Distributor ID:)\s*(.*)", re.I)
_release_cmdline_re = re.compile("(?:Release:)\s*(.*)", re.I)
_distributor_id_file_re = re.compile("(?:DISTRIB_ID\s*=)\s*(.*)", re.I)
_release_file_re = re.compile("(?:DISTRIB_RELEASE\s*=)\s*(.*)", re.I)
global _distname,_version
_distname = None
_version = None
def get_linux_distro():
""" Tries to determine the name of the Linux OS distribution name.
First, try to parse a file named "/etc/lsb-release". If it exists, and
contains the "DISTRIB_ID=" line and the "DISTRIB_RELEASE=" line, then return
the strings parsed from that file.
If that doesn't work, then invoke platform.dist().
If that doesn't work, then try to execute "lsb_release", as standardized in
2001:
http://refspecs.freestandards.org/LSB_1.0.0/gLSB/lsbrelease.html
The current version of the standard is here:
http://refspecs.freestandards.org/LSB_3.2.0/LSB-Core-generic/LSB-Core-generic/lsbrelease.html
that lsb_release emitted, as strings.
Returns a tuple (distname,version). Distname is what LSB calls a
"distributor id", e.g. "Ubuntu". Version is what LSB calls a "release",
e.g. "8.04".
A version of this has been submitted to python as a patch for the standard
library module "platform":
http://bugs.python.org/issue3937
"""
global _distname,_version
if _distname and _version:
return (_distname, _version)
try:
etclsbrel = open("/etc/lsb-release", "rU")
for line in etclsbrel:
m = _distributor_id_file_re.search(line)
if m:
_distname = m.group(1).strip()
if _distname and _version:
return (_distname, _version)
m = _release_file_re.search(line)
if m:
_version = m.group(1).strip()
if _distname and _version:
return (_distname, _version)
except EnvironmentError:
pass
(_distname, _version) = platform.dist()[:2]
if _distname and _version:
return (_distname, _version)
try:
p = subprocess.Popen(["lsb_release", "--all"], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
rc = p.wait()
if rc == 0:
for line in p.stdout.readlines():
m = _distributor_id_cmdline_re.search(line)
if m:
_distname = m.group(1).strip()
if _distname and _version:
return (_distname, _version)
m = _release_cmdline_re.search(p.stdout.read())
if m:
_version = m.group(1).strip()
if _distname and _version:
return (_distname, _version)
except EnvironmentError:
pass
if os.path.exists("/etc/arch-release"):
return ("Arch_Linux", "")
return (_distname,_version)
def get_platform():
# Our version of platform.platform(), telling us both less and more than the
# Python Standard Library's version does.
# We omit details such as the Linux kernel version number, but we add a
# more detailed and correct rendition of the Linux distribution and
# distribution-version.
if "linux" in platform.system().lower():
return platform.system()+"-"+"_".join(get_linux_distro())+"-"+platform.machine()+"-"+"_".join([x for x in platform.architecture() if x])
else:
return platform.platform()
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