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driving_force_extension.py
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driving_force_extension.py
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#!/usr/bin/env python
# coding: utf-8
# # Driving force extension method - hands-on tutorial
# Reference:
#
# > J. Zhang, A. F. Chadwick, D. L. Chopp, P. W. Voorhees, “Phase Field Modeling with Large Driving Forces,” npj Computational Materials, 9 (2023) 166. doi: [10.1038/s41524-023-01118-0](https://doi.org/10.1038/s41524-023-01118-0)
# # Introduction
#
# Phase field equation typically has the following form
# $$
# \tau\frac{\partial \phi}{\partial t} = \kappa \nabla^2{\phi} - m g'(\phi) - p'(\phi) F
# $$
# where $F$ is the driving force. Phase field simulations with a large driving force and a large grid size can be unstable.
#
#
# ![unstable](img/stability.png) |
# -
#
# The driving force extension method introduces a simple modification of the equation
# $$
# \tau\frac{\partial \phi}{\partial t} = \kappa \nabla^2{\phi} - m g'(\phi) - p'(\phi) \mathcal{P}(F),
# $$
# where $\mathcal{P}$ projects $F$ to a constant perpendicular to the interface:
# $$
# \mathcal{P}(F(\vec{x}, t)) = F(\vec{x}_\Gamma, t).
# $$
# Here, $\vec{x}_\Gamma$ is the closest point on the interface $\Gamma$:
# $$
# \vec{x}_\Gamma(\vec{x}) = \{\vec{y} : \min_{\vec{y}\in \Gamma} |{\vec{y}-\vec{x}}|\}
# $$
#
# ![unstable](img/mapping.png) |
# -
#
# Let's use the KKS model for demonstration.
# # KKS model
#
# Here I use the KKS model<sup>[1]</sup> as an example. Let's first briefly overview the KKS model.
#
# The free energy of the system is
# $$
# F[\phi, c] = \int{\frac{1}{2}\kappa |{\nabla{\phi}}^2| + m g(\phi) + p(\phi) f^s(c^s)+(1-p(\phi))f^l(c^l) }{\, \mathrm{d} V},
# $$
# where $\phi$ is the phase field variable and $c$ is concentration.
#
# Two constraints need to be fulfilled. First, the total concentration is interpolated between the phase concentrations
# $$
# c = p(\phi) c^s + (1-p(\phi)) c^l.
# $$
# Second, the quasi-local-equilibrium constraint
# $$
# \tilde{\mu} = \frac{\mathrm{d} f^s}{\mathrm{d} c^s} = \frac{\mathrm{d} f^l}{\mathrm{d} c^l},
# $$
# where $\tilde{\mu}$ is the diffusion potential. We can solve the phase concentration $c^s$ and $c^l$ from the phase field $\phi$ and the total concentration $c$ from these two constraints.
#
# The evolution equations for the KKS model are
# $$
# \frac{1}{L} \frac{\partial \phi}{\partial t} = \kappa \nabla^2{\phi} - m g'(\phi) - p'(\phi) \left(f^s -f^l - (c^s-c^l) \tilde{\mu} \right),
# $$
# $$
# \frac{\partial c}{\partial t} = \nabla\cdot{\left(M \nabla{\tilde{\mu}}\right)}.
# $$
#
# [1] SG Kim, WT Kim, and T Suzuki. Phase-field model for binary alloys. Physical Review E, 60(6), 7186-7197 (1999).
# ### Simple case
# To make life easier and focus on the stability problem of large driving forces, we make the following assumptions.
#
# First, we assume a parabolic free energy
# $$
# f^\alpha(c^\alpha) = \frac{1}{2} B (c^\alpha-c^\alpha_0)^2.
# $$
# Note we assume $A^s=A^l=0$ and $B^s=B^l=B$.
#
# Second, we assume $D=D^s=D^l$.
#
# Third, we assume the interface is at local equilibrium, so the phase field mobility $L$ is
# $$
# L = \frac{D}{6 a l^2 B \Delta c_0^2},
# $$
# where $l$ is diffuse interface width, $\Delta c_0 = c_0^l-c_0^s$, $a=5/6$ for third-order interpolation $p(\phi)=\phi^3(3-2\phi)$ and $a=47/60$ for fifth-order interpolation $p(\phi)=\phi^3(6\phi^2-15\phi+10)$.
# ### Nondimensionalization
# We nondimensionalize length by the system size $L_{\text{sys}}$, time by the diffusion timescale $L_{\text{sys}}^2/D$, energy density by $RT/V_m$, concentration by $1/V_m$.
#
# The dimensionless evolution equations are
# $$
# b \frac{\partial \phi}{\partial t} = \gamma \left(\epsilon^2 \nabla^2{\phi} - \frac{1}{2} g'(\phi)\right) - p'(\phi) F,
# $$
# $$
# B \frac{\partial x}{\partial t} = \nabla^2{\tilde{\mu}},
# $$
# where $b=6a \epsilon^2 \Delta x_0^2 B$, $\epsilon = l/L_{\text{sys}}$ is the dimensionless interface width, $\gamma = 6 \sigma V_m/(RTl)$ is the dimensionless surface energy, molar fraction $x = V_m c$, and $\Delta x_0 = x_0^l-x_0^s$.
#
# The dimensionless diffusion potential is
# $$
# \tilde{\mu} = B \left(x - p(\phi) x_0^s - (1-p) x_0^l\right).
# $$
# The dimensionless driving force is
# $$
# F = \tilde{\mu} \Delta x_0.
# $$
# Clearly, $F$ scales with $B$.
# ### Driving force extension method
# The driving force extension method introduces a simple modification of the phase field equation:
# $$
# b \frac{\partial \phi}{\partial t} = \gamma \left(\epsilon^2 \nabla^2{\phi} - \frac{1}{2} g'(\phi)\right) - p'(u) \color{red}{\mathcal{P}(F)},
# $$
# # Implementation
#
# For simplicity, let's use a 1D case.
# Let's import the needed packages. Here we only need *numpy* and *matplotlib*. If you don't have them installed, use the following command
# In[ ]:
get_ipython().system('pip install numpy matplotlib')
# In[ ]:
# import needed packages
import numpy as np
import matplotlib.pyplot as plt
# Let's define some useful functions. Note that I use cell-based finite difference.
# In[ ]:
def dg(x): # 0.5 * g'(x)
return x * (1-x) * (1-2*x)
def laplacian_1d(u, dx): # laplacian of u
return (u[2:] + u[0:-2] - 2.0 * u[1:-1]) / dx ** 2
def apply_bc(phi, c, xl, xr): # apply boundary conditions
phi[0] = phi[1] # no-flux
phi[-1] = phi[-2] # no-flux
c[0] = 2 * xl - c[1] # dirichlet
c[-1] = 2 * xr - c[-2] # dirichlet
# Let's now implement the driving force extension $\mathcal{P}(f)$. The algorithm has been well-developed in the level-set community and is called the velocity extension<sup>[2]</sup>. The following considers a very simple case: a single interface inside a 1D domain. A general algorithm is needed for more general cases. We will talk about this later.
#
# [2] Adalsteinsson, D. and Sethian, J. The fast construction of extension velocities in level set methods. J. Comput. Phys. 148, 2-22 (1999).
# In[ ]:
# velocity extension, u is the level-set, u=0 gives the location of the interface
def velext_simple(u, f):
i = np.where(u[:-1] * u[1:] < 0)[0][0] # find place where u crosses zero
return (f[i+1]*u[i] - f[i]*u[i+1]) / (u[i]-u[i+1]) # linear interpolation
# $u=0$ gives the location of the interface $\Gamma$. You can use $u=\phi-0.5$.
# Let's do a quick test.
# In[ ]:
x = np.linspace(0, 1, 20)-0.42 # coordinate
u = x # interface is at x=0
f = np.sinh(x*4)+1 # driving force
pf=velext_simple(u, f) # projected driving force
plt.plot(u,f, label='F')
plt.plot(u,np.full_like(u,pf), label='P(F)')
plt.legend()
# Now, let's implement the KKS model. We set $x_0^s=0.1$ and $x_0^l=0.9$. The molar fraction at the right boundary is fixed to be $x_0=0.5$.
# In[ ]:
def kks1d(B, dx=0.01, ptype='3rd', dfe=True):
'''
B : [] parabolic free energy parameter
dx : [] grid size
ptype : type of interpolation function
dfe : whether we apply for the driving force extension
------
assume D=D^s=D^l, B=B^s=B^l
'''
# interpolation function
if ptype == '3rd':
pfun = lambda x : x**2 * (3.0 - 2.0 * x)
dpfun = lambda x : 6.0 * x * (1-x)
elif ptype == '5th':
pfun = lambda x : x**3 * (6.0 * x**2 - 15.0 * x + 10.0)
dpfun = lambda x : 30 * x**2 * (1-x)**2
# geometry
L = 1.28 # [] size of the whole system
Li = 0.28 # [] initial location of the interface
epsilon = 1.5*dx # [] dimensionless interface width
# parameters
T = 298.15 # [K] temperature
R = 8.314 # [J/K mol] gass constant
Vm = 1.1e-5 # [m^3/mol] molar volume
Lsys = 100e-6 # [m] system size
sigma = 0.5 # [J/m^2] surface energy
gamma = 6*sigma*Vm/(R*T*epsilon*Lsys) # [] dimensionless surface energy
x0s = 0.1 # [] parabolic free energy parameter
x0l = 0.9 # [] parabolic free energy parameter
x0 = 0.5 # [] far field concentration
a = 5.0 / 6.0 if ptype == '3rd' else 47.0 / 60.0
one_over_b = 1.0/(6*a*( epsilon * (x0l-x0s) )**2 * B) # [] 1/b
dt = dx**2/8.0 # [] timestep size
# initial condition
nx = int(L/dx) # number of interior grids
X = np.linspace(-0.5, nx + 0.5, nx + 2) * dx - Li # [] coordinate
phi = 0.5 * (1.0 - np.tanh(0.5 * X / epsilon)) # [] phase field
xl = x0l + (X > 0) * X / (L - Li) * (x0 - x0l) # [] assume an initial linear profile
p = pfun(phi)
c = p * x0s + (1-p)*xl # [] concentration
apply_bc(phi, c, x0s, x0)
# time loop
nt = int(0.6/dt)
for t in range(0, nt): #
p = pfun(phi)
dp = dpfun(phi)[1:-1]
mu_over_B = c - p*x0s - (1-p)*x0l # diffusion potential
F = B * mu_over_B * (x0l-x0s) # driving force
PF = velext_simple(phi-0.5,F) if dfe else F[1:-1] # driving force extension
# forward Euler
dphi = dt * one_over_b * (gamma * (epsilon**2 * laplacian_1d(phi, dx) - dg(phi[1:-1])) - dp*PF)
dc = dt * laplacian_1d(mu_over_B, dx)
# update
phi[1:-1] += dphi
c[1:-1] += dc
apply_bc(phi, c, x0s, x0)
# plotting
plt.clf()
plt.plot(X,phi, label='phi')
plt.plot(X,c, label='c')
plt.legend()
# Let's try it!
# In[ ]:
get_ipython().run_cell_magic('time', '', "kks1d(B=0.001, dx=0.01, ptype='3rd', dfe=False)\n")
# In[ ]:
get_ipython().run_cell_magic('time', '', "kks1d(B=0.01, dx=0.01, ptype='3rd', dfe=False)\n")
# In[ ]:
get_ipython().run_cell_magic('time', '', "kks1d(B=0.01, dx=0.01, ptype='5th', dfe=False)\n")
# In[ ]:
get_ipython().run_cell_magic('time', '', "kks1d(B=0.1, dx=0.01, ptype='5th', dfe=False)\n")
# In[ ]:
get_ipython().run_cell_magic('time', '', "kks1d(B=0.1, dx=0.005, ptype='5th', dfe=False)\n")
# In[ ]:
get_ipython().run_cell_magic('time', '', "kks1d(B=1.0, dx=0.005, ptype='5th', dfe=False)\n")
# You will get something like
#
# ![result](img/kks_stability.png) |
# -
#
# For the case of the original model, the 5-th order interpolation is more stable than the 3-rd order interpolation. However, they both have an upper bound on the magnitude of the driving force.
# In[ ]:
get_ipython().run_cell_magic('time', '', "kks1d(B=1.0, dx=0.01, ptype='3rd', dfe=True)\n")
# The driving force extension method does not have this upper bound.
# ## Velocity extension for general cases
# For more general cases, we need more complex velocity extension algorithms. See Ref.[3] for a review. Following is a modified version of the Fast Sweep Method/Fast Iterative Method for the 1D case.
#
# [3] Gómez et al, Fast methods for Eikonal equations: an experimental survey, IEEE Access (2019)
# In[ ]:
def velext_fim(u, f): # velocity extension general 1D case (fast iterative method)
nx = u.shape[0]
d = np.full_like(u, np.inf) # distance function
s = np.full_like(u, 2, dtype=int) # 1 - distant, 0 - tentative, -1 - initialize, -2 - converged
w = np.empty_like(f) # extended driving force
id = np.where(u[:-1] * u[1:] < 0)[0]
assert id.size, "no interface!"
for i in id:
s[i:i+2] = -1
t_ = np.abs(u[i] / (u[i]-u[i+1])) # linear interpolation
d[i] = t_
d[i+1] = 1-t_
w[i+1] = w[i] = (1-t_)*f[i] + t_*f[i+1] # extended driving force
while np.any(s>-1): # loop until everything is converged
for i in range(0, nx-1, 1): # sweep ->
if s[i] < 1 and s[i+1] > -1:
d_ = d[i] + 1
r_ = d[i+1] - d_ # difference
if r_ >= 0:
d[i+1] = d_ # update
if r_ == 0 and s[i] < 0:
s[i+1] = -2 # converged
w[i+1] = w[i]
else:
s[i+1] = 0 # active
for i in range(nx-1, 0, -1): # sweep <-
if s[i] < 1 and s[i-1] > -1:
d_ = d[i] + 1
r_ = d[i-1] - d_ # difference
if r_ >= 0:
d[i-1] = d_ # update
if r_ == 0 and s[i] < 0:
s[i-1] = -2 # converged
w[i-1] = w[i]
else:
s[i-1] = 0 # active
return w[1:-1] # without ghost layer
# Let's test it.
# In[ ]:
x = np.linspace(0, 1, 20)-0.42
u = x**2-0.05
f = np.sinh(x*4)+1
pf=velext_fim(u, f)
plt.subplot(211)
plt.plot(x[1:-1],u[1:-1], label='u')
plt.plot(x[1:-1],0*u[1:-1], label='0')
plt.legend()
plt.subplot(212)
plt.plot(x[1:-1],f[1:-1], label='F')
plt.plot(x[1:-1],pf, label='P(F)')
plt.legend()
# You can try it in the KKS code, just change from 'velext_simple' to 'velext_fim'. Note the 'velext_fim' code is not optimized.
# # Summary
#
# The driving force extension method can solve the stability problem with a large driving force. It is simple because you can easily combine it with your existing phase field code.
#
# You can find more details in our paper. For questions, comments, suggestions, or bug reports, email me at [jzhang\@northwestern.edu](mailto:jzhang@northwestern.edu) or visit [github](https://github.com/jijn/dfe_tutorial).