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Yet another page done.

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1 parent e61722d commit 5b1e301a3e17257adca7770c4bd481001cc4d0c4 @jlouis committed May 23, 2009
Showing with 3 additions and 3 deletions.
  1. +3 −3 report/janus0.tex
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@@ -197,7 +197,7 @@ \subsection{Properties of stores}
\end{proof}
The following property states that ``if you have enough pieces placed
-correctly you have the whole puzzle''; that is, if you enough about a
+correctly you have the whole puzzle''; that is, if you know enough about a
store, you can decide its equality:
\begin{lem}
\label{lem:hide-eq}
@@ -208,7 +208,7 @@ \subsection{Properties of stores}
\item $\sigma'(x) = v$
\item $(\sigma \setminus x) = (\sigma' \setminus x)$
\end{itemize}
- Then $\sigma = sigma'$
+ Then $\sigma = \sigma'$
\end{lem}
\begin{proof}
By \coq{}.
@@ -237,7 +237,7 @@ \subsection{Properties of stores}
\begin{proof}
In \coq{}. The proof relies on backwards reasoning. It uses
extensionality (see \ref{coqext:extensionality}) and then it uses
- case analysis. In the cases, it applies lemma \eqref{lem:hide_ne}.
+ case analysis. In the cases, it applies Lemma \ref{lem:hide_ne}.
\end{proof}
Another very important concept is that a write to the hidden variable

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