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Here's my anagram counter. It is roughly consistent with usual descriptions of anagram counting problems. Specifically, this is a solution for the problem: "Given a set of words, output the number of words in that set that have at least one anagram among the other words in the set."

Note that a word is an anagram of itself. Words are also restricted to alphabetical characters, and our comparisons are case-insensitive.

Some notes on usage:

From the anagram-analyzer directory, you can either: run the tests (./, to see that things are working run the program on your own data (./ ) NOTE: You'll need python installed to run the scripts. I've tested them on python 2.7.3 and 3.3.2 .

If you are running the program on your own data, your word file should contain one word per line. Words should conform to the following restrictions: only alphabetical characters, no numbers, whitespace, or punctuation. Words should be immediately followed by a newline.

For convenience (and fun,) I've included a few word lists in the ./wordlists directory. The small ones are for my own testing, and the large ones were found here and here. They show that the algorithm runs decently fast on large inputs. (These files are the reason the directory is so huge, but I figured it would be nice to see the code run on them.)

Time complexity: Roughly speaking, the algorithm is doing the following: Building a word list (n steps) Constructing a tuple of letters in each word (n steps) Looking this tuple up in a dict, and incrementing a value (constant time increase) Summing the values in the dict (n steps) Because the running time of the algorithm is a constant multiple of n, the algorithm should be O(n). Interestingly, there is a sorting operation happening when the tuples are constructed (each word's letters are sorted alphabetically. However, since this word length doesn't depend on the input size n and can't be described in terms of n, I believe it's fine to exclude that step from the O() notation. If you were to describe the input as a list of n words, with a total of m characters, then the running time might be something more like n * (n/m)log(n/m), because for each term, we're sorting its n/m letters.


Outputs the number of words with anagrams in the given word file



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