Skip to content
This repository

HTTPS clone URL

Subversion checkout URL

You can clone with HTTPS or Subversion.

Download ZIP

Return Python objects, always get JSON.

branch: master
README.rst

django-jsonview

https://travis-ci.org/jsocol/django-jsonview.png?branch=master

django-jsonview is a simple decorator that translates Python objects to JSON and makes sure your view will always return JSON.

I've copied and pasted this so often I decided I just wanted to put it in a package.

Installation

Just install with pip:

pip install django-jsonview

No need to add to INSTALLED_APPS or anything.

Usage

Just import the decorator, use, and return a JSON-serializable object:

from jsonview.decorators import json_view

@json_view
def my_view(request):
    return {
        'foo': 'bar',
    }

Content Types

If you need to return a content type other than the standard application/json, you can specify that in the decorator with the content_type argument, for example:

from jsonview.decorators import json_view

@json_view(content_type='application/vnd.github+json')
def myview(request):
    return {'foo': 'bar'}

The response will have the appropriate content type header.

Return Values

The default case is to serialize your return value and respond with HTTP 200 and a Content-Type of application/json.

The @json_view decorator will handle many exceptions and other cases, including:

  • Http404
  • PermissionDenied
  • HttpResponseNotAllowed (e.g. require_GET, require_POST)
  • jsonview.exceptions.BadRequest (see below)
  • Any other exception (logged to django.request).

Any of these exceptions will return the correct status code (i.e., 404, 403, 405, 400, 500) a Content-Type of application/json, and a response body that looks like:

json.dumps({
    'error': STATUS_CODE,
    'message': str(exception),
})

Note

As of v0.4, application exceptions do not behave this way if DEBUG = False. When DEBUG = False, the message value is always An error occurred. When DEBUG = True, the exception message is sent back.

BadRequest

HTTP does not have a great status code for "you submitted a form that didn't validate," and so Django doesn't support it very well. Most examples just return 200 OK.

Normally, this is fine. But if you're submitting a form via Ajax, it's nice to have a distinct status for "OK" and "Nope." The HTTP 400 Bad Request response is the fallback for issues with a request not-otherwise-specified, so let's do that.

To cause @json_view to return a 400, just raise a jsonview.exceptions.BadRequest with whatever appropriate error message.

Exceptions

If your view raises an exception, @json_view will catch the exception, log it to the normal django.request logger, and return a JSON response with a status of 500 and a body that looks like the exceptions in the Return Values section.

Note

Because the @json_view decorator handles the exception instead of propagating it, any exception middleware will not be called, and any response middleware will be called.

Status Codes

If you need to return a different HTTP status code, just return two values instead of one. The first is your serializable object, the second is the integer status code:

@json_view
def myview(request):
    if not request.user.is_subscribed():
        # Send a 402 Payment Required status.
        return {'subscribed': False}, 402
    # Send a 200 OK.
    return {'subscribed': True}

Extra Headers

You can add custom headers to the response by returning a tuple of three values: an object, a status code, and a dictionary of headers.

@json_view
def myview(request):
    return {}, 200, {'X-Server': 'myserver'}

Custom header values may be overwritten by response middleware.

Raw Return Values

To make it possible to cache JSON responses as strings (and because they aren't JSON serializable anyway) if you return an HttpResponse object (or subclass) it will be passed through unchanged, e.g.:

from django import http
from jsonview.decorators import JSON

@json_view
def caching_view(request):
    kached = cache.get('cache-key')
    if kached:
        return http.HttpResponse(kached, content_type=JSON)
    # Assuming something else populates this cache.
    return {'complicated': 'object'}

Note

@require_POST and the other HTTP method decorators work by returning a response, rather than raising, an an exception, so HttpResponseNotAllowed is handled specially.

Alternative JSON Implementations

There is a healthy collection of JSON parsing and generating libraries out there. By default, it will use the old standby, the stdlib json module. But, if you'd rather use ujson, or cjson or yajl, you should go for it. Just add this to your Django settings:

JSON_MODULE = 'ujson'

Anything, as long as it's a module that has .loads() and .dumps() methods.

Contributing

Pull requests and issues welcome! I ask two simple things:

  • Tests, including the new ones you added, must pass. (See below.)
  • The flake8 tool should not return any issues.

Running Tests

To run the tests, you probably want to create a virtualenv, then install Django and Mock with pip:

pip install Django==${DJANGO_VERSION} mock==1.0.1

Then run the tests with:

./run.sh test
Something went wrong with that request. Please try again.