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Wrong extra hint on end of solving quads by fact.

Fixes Open #33388 #33076 #33077 Closed #31645 #29435 #30472 #30400
#27614
Solving quadratics by factoring (& 2) added and extra hint for the
one-root problem.  Both used appendContents but recently multiple
problem had one more hint than one-root problem added.  Kept the new
text, but merged the new hint with old.
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commit fe5ed186bae8b63e6fd1b4986252c1e85283c6e6 1 parent dbb22c4
@karlanderson authored
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14 exercises/solving_quadratics_by_factoring.html
@@ -56,13 +56,13 @@
So <code>(x <var>A &lt; 0 ? "+" : ""</var> \color{<var>PINK</var>}{<var>-A</var>})
(x <var>B &lt; 0 ? "+" : ""</var> \color{<var>PINK</var>}{<var>-B</var>}) = 0</code>.
</p>
- <p id="hint3">
- Since <code>(x <var>A &lt; 0 ? "+" : ""</var> <var>-A</var>)
- (x <var>B &lt; 0 ? "+" : ""</var> <var>-B</var>) = 0</code>,
- we know that one or both quantities must equal zero for the equation to be true.
- </p>
- <p id="hint4"><code>x + <var>-A</var> = 0</code> or <code>x + <var>-B</var> = 0</code></p>
- <p id="hint5"><b>Thus, <code>x = <var>A</var></code> and <code>x = <var>B</var></code> are the solutions.</b></p>
+ <div id="hint3">
+ <p>Since <code>(x <var>A &lt; 0 ? "+" : ""</var> <var>-A</var>)
+ (x <var>B &lt; 0 ? "+" : ""</var> <var>-B</var>) = 0</code>,
+ we know that one or both quantities must equal zero for the equation to be true.</p>
+ <p><code>x + <var>-A</var> = 0</code> or <code>x + <var>-B</var> = 0</code></p>
+ </div>
+ <p id="hint4"><b>Thus, <code>x = <var>A</var></code> and <code>x = <var>B</var></code> are the solutions.</b></p>
</div>
</div>
View
14 exercises/solving_quadratics_by_factoring_2.html
@@ -56,13 +56,13 @@
So <code>(x <var>A &lt; 0 ? "+" : ""</var> \color{<var>PINK</var>}{<var>-A</var>})
(x <var>B &lt; 0 ? "+" : ""</var> \color{<var>PINK</var>}{<var>-B</var>}) = 0</code>.
</p>
- <p id="hint3">
- Since <code>(x <var>A &lt; 0 ? "+" : ""</var> <var>-A</var>)
- (x <var>B &lt; 0 ? "+" : ""</var> <var>-B</var>) = 0</code>,
- we know that one or both quantities must equal zero for the equation to be true.
- </p>
- <p id="hint4"><code>x + <var>-A</var> = 0</code> or <code>x + <var>-B</var> = 0</code></p>
- <p id="hint5"><b>Thus, <code>x = <var>A</var></code> and <code>x = <var>B</var></code> are the solutions.</b></p>
+ <div id="hint3">
+ <p>Since <code>(x <var>A &lt; 0 ? "+" : ""</var> <var>-A</var>)
+ (x <var>B &lt; 0 ? "+" : ""</var> <var>-B</var>) = 0</code>,
+ we know that one or both quantities must equal zero for the equation to be true.</p>
+ <p><code>x + <var>-A</var> = 0</code> or <code>x + <var>-B</var> = 0</code></p>
+ </div>
+ <p id="hint4"><b>Thus, <code>x = <var>A</var></code> and <code>x = <var>B</var></code> are the solutions.</b></p>
</div>
</div>
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