Test Driven Development Exercise - Synacor VM
This repo contains an implementation of the Synacor Challenge VM with tests written using the Snow library. A blog post about the development can be located here.
== architecture ==
- three storage regions
- memory with 15-bit address space storing 16-bit values
- eight registers
- an unbounded stack which holds individual 16-bit values
- all numbers are unsigned integers 0..32767 (15-bit)
- all math is modulo 32768; 32758 + 15 => 5
== binary format ==
- each number is stored as a 16-bit little-endian pair (low byte, high byte)
- numbers 0..32767 mean a literal value
- numbers 32768..32775 instead mean registers 0..7
- numbers 32776..65535 are invalid
- programs are loaded into memory starting at address 0
- address 0 is the first 16-bit value, address 1 is the second 16-bit value, etc
== execution ==
- After an operation is executed, the next instruction to read is immediately after the last argument of the current operation. If a jump was performed, the next operation is instead the exact destination of the jump.
- Encountering a register as an operation argument should be taken as reading from the register or setting into the register as appropriate.
== hints ==
- The program "9,32768,32769,4,19,32768" occupies six memory addresses and should:
- Store into register 0 the sum of 4 and the value contained in register 1.
- Output to the terminal the character with the ascii code contained in register 0.
== opcode listing ==
halt: 0 stop execution and terminate the program set: 1 a b set register <a> to the value of <b> push: 2 a push <a> onto the stack pop: 3 a remove the top element from the stack and write it into <a>; empty stack = error eq: 4 a b c set <a> to 1 if <b> is equal to <c>; set it to 0 otherwise gt: 5 a b c set <a> to 1 if <b> is greater than <c>; set it to 0 otherwise jmp: 6 a jump to <a> jt: 7 a b if <a> is nonzero, jump to <b> jf: 8 a b if <a> is zero, jump to <b> add: 9 a b c assign into <a> the sum of <b> and <c> (modulo 32768) mult: 10 a b c store into <a> the product of <b> and <c> (modulo 32768) mod: 11 a b c store into <a> the remainder of <b> divided by <c> and: 12 a b c stores into <a> the bitwise and of <b> and <c> or: 13 a b c stores into <a> the bitwise or of <b> and <c> not: 14 a b stores 15-bit bitwise inverse of <b> in <a> rmem: 15 a b read memory at address <b> and write it to <a> wmem: 16 a b write the value from <b> into memory at address <a> call: 17 a write the address of the next instruction to the stack and jump to <a> ret: 18 remove the top element from the stack and jump to it; empty stack = halt out: 19 a write the character represented by ascii code <a> to the terminal in: 20 a read a character from the terminal and write its ascii code to <a>; it can be assumed that once input starts, it will continue until a newline is encountered; this means that you can safely read whole lines from the keyboard and trust that they will be fully read noop: 21 no operation