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backport: Improve performance of p2p inv to send queues bitcoin#27610
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losh11 committed Mar 3, 2024
1 parent 260de84 commit 2170c24
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Showing 2 changed files with 11 additions and 4 deletions.
4 changes: 3 additions & 1 deletion src/net_processing.cpp
Original file line number Diff line number Diff line change
Expand Up @@ -4759,7 +4759,9 @@ bool PeerManager::SendMessages(CNode* pto)
// especially since we have many peers and some will draw much shorter delays.
unsigned int nRelayedTransactions = 0;
LOCK(pto->m_tx_relay->cs_filter);
while (!vInvTx.empty() && nRelayedTransactions < INVENTORY_BROADCAST_MAX) {
size_t broadcast_max{INVENTORY_BROADCAST_MAX + (pto->m_tx_relay->setInventoryTxToSend.size()/1000)*5};
broadcast_max = std::min<size_t>(1000, broadcast_max);
while (!vInvTx.empty() && nRelayedTransactions < broadcast_max) {
// Fetch the top element from the heap
std::pop_heap(vInvTx.begin(), vInvTx.end(), compareInvMempoolOrder);
std::set<uint256>::iterator it = vInvTx.back();
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11 changes: 8 additions & 3 deletions src/txmempool.cpp
Original file line number Diff line number Diff line change
Expand Up @@ -818,11 +818,16 @@ void CTxMemPool::check(const CCoinsViewCache *pcoins) const

bool CTxMemPool::CompareDepthAndScore(const uint256& hasha, const uint256& hashb, bool wtxid)
{
/* Return `true` if hasha should be considered sooner than hashb. Namely when:
* a is not in the mempool, but b is
* both are in the mempool and a has fewer ancestors than b
* both are in the mempool and a has a higher score than b
*/
LOCK(cs);
indexed_transaction_set::const_iterator i = wtxid ? get_iter_from_wtxid(hasha) : mapTx.find(hasha);
if (i == mapTx.end()) return false;
indexed_transaction_set::const_iterator j = wtxid ? get_iter_from_wtxid(hashb) : mapTx.find(hashb);
if (j == mapTx.end()) return true;
if (j == mapTx.end()) return false;
indexed_transaction_set::const_iterator i = wtxid ? get_iter_from_wtxid(hasha) : mapTx.find(hasha);
if (i == mapTx.end()) return true;
uint64_t counta = i->GetCountWithAncestors();
uint64_t countb = j->GetCountWithAncestors();
if (counta == countb) {
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