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[mlir:Async] Remove async operations if it is statically known that t…
…he parallel operation has a single compute block Depends On D104850 Add a test that verifies that canonicalization removes all async overheads if it is statically known that the scf.parallel operation will be computed using a single block. Reviewed By: herhut Differential Revision: https://reviews.llvm.org/D104891
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mlir/test/Dialect/Async/async-parallel-for-canonicalize.mlir
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// RUN: mlir-opt %s \ | ||
// RUN: -async-parallel-for=async-dispatch=true \ | ||
// RUN: -canonicalize -inline -symbol-dce \ | ||
// RUN: | FileCheck %s | ||
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// RUN: mlir-opt %s \ | ||
// RUN: -async-parallel-for=async-dispatch=false \ | ||
// RUN: -canonicalize -inline -symbol-dce \ | ||
// RUN: | FileCheck %s | ||
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// Check that if we statically know that the parallel operation has a single | ||
// block then all async operations will be canonicalized away and we will | ||
// end up with a single synchonous compute function call. | ||
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// CHECK-LABEL: @loop_1d( | ||
// CHECK: %[[MEMREF:.*]]: memref<?xf32> | ||
func @loop_1d(%arg0: memref<?xf32>) { | ||
// CHECK-DAG: %[[C0:.*]] = constant 0 : index | ||
// CHECK-DAG: %[[C1:.*]] = constant 1 : index | ||
// CHECK-DAG: %[[C100:.*]] = constant 100 : index | ||
// CHECK-DAG: %[[ONE:.*]] = constant 1.000000e+00 : f32 | ||
// CHECK: scf.for %[[I:.*]] = %[[C0]] to %[[C100]] step %[[C1]] | ||
// CHECK: memref.store %[[ONE]], %[[MEMREF]][%[[I]]] | ||
%lb = constant 0 : index | ||
%ub = constant 100 : index | ||
%st = constant 1 : index | ||
scf.parallel (%i) = (%lb) to (%ub) step (%st) { | ||
%one = constant 1.0 : f32 | ||
memref.store %one, %arg0[%i] : memref<?xf32> | ||
} | ||
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return | ||
} |