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Pyramid parser use_kwargs throws exception when used #42

hartror opened this issue May 20, 2015 · 0 comments


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commented May 20, 2015

The following code using the pyramid parser throws an exception:

@parser.use_kwargs({'myvalue': Arg(int)})
def baz(request, myvalue):
    return {'myvalue': myvalue}

The exception:

        kwargs['as_kwargs'] = True
>       return self.use_args(*args, **kwargs)
E       TypeError: use_args() got an unexpected keyword argument 'as_kwargs'
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