From 0aa1aa1ebc2d3f18d1016f65402530f605dc61e5 Mon Sep 17 00:00:00 2001 From: Claire Date: Wed, 6 Apr 2022 14:03:48 +0200 Subject: [PATCH] Fix possible duplicate statuses in timelines in some edge cases In some rare cases, when receiving statuses out of order from the streaming API then polling from the REST API, it was possible for the `expandNormalizedTimeline` function to insert duplicates in the timeline, which would then result in several bugs. This commits ensures that there are no duplicates inserted in the timeline. --- app/javascript/mastodon/reducers/timelines.js | 37 ++++++++++++++++--- 1 file changed, 31 insertions(+), 6 deletions(-) diff --git a/app/javascript/mastodon/reducers/timelines.js b/app/javascript/mastodon/reducers/timelines.js index b66c19fd5e837..301997567f7c8 100644 --- a/app/javascript/mastodon/reducers/timelines.js +++ b/app/javascript/mastodon/reducers/timelines.js @@ -16,7 +16,7 @@ import { ACCOUNT_MUTE_SUCCESS, ACCOUNT_UNFOLLOW_SUCCESS, } from '../actions/accounts'; -import { Map as ImmutableMap, List as ImmutableList, fromJS } from 'immutable'; +import { Map as ImmutableMap, List as ImmutableList, OrderedSet as ImmutableOrderedSet, fromJS } from 'immutable'; import compareId from '../compare_id'; const initialState = ImmutableMap(); @@ -32,6 +32,13 @@ const initialTimeline = ImmutableMap({ }); const expandNormalizedTimeline = (state, timeline, statuses, next, isPartial, isLoadingRecent, usePendingItems) => { + // This method is pretty tricky because: + // - existing items in the timeline might be out of order + // - the existing timeline may have gaps, most often explicitly noted with a `null` item + // - ideally, we don't want it to reorder existing items of the timeline + // - `statuses` may include items that are already included in the timeline + // - this function can be called either to fill in a gap, or load newer items + return state.update(timeline, initialTimeline, map => map.withMutations(mMap => { mMap.set('isLoading', false); mMap.set('isPartial', isPartial); @@ -46,15 +53,33 @@ const expandNormalizedTimeline = (state, timeline, statuses, next, isPartial, is mMap.update(usePendingItems ? 'pendingItems' : 'items', ImmutableList(), oldIds => { const newIds = statuses.map(status => status.get('id')); + // Now this gets tricky, as we don't necessarily know for sure where the gap to fill is + // and some items in the timeline may not be properly ordered. + + // However, we know that `newIds.last()` is the oldest item that was requested and that + // there is no “hole” between `newIds.last()` and `newIds.first()`. + + // First, find the furthest (if properly sorted, oldest) item in the timeline that is + // newer than the oldest fetched one, as it's most likely that it delimits the gap. + // Start the gap *after* that item. const lastIndex = oldIds.findLastIndex(id => id !== null && compareId(id, newIds.last()) >= 0) + 1; - const firstIndex = oldIds.take(lastIndex).findLastIndex(id => id !== null && compareId(id, newIds.first()) > 0); - if (firstIndex < 0) { - return (isPartial ? newIds.unshift(null) : newIds).concat(oldIds.skip(lastIndex)); + // Then, try to find the furthest (if properly sorted, oldest) item in the timeline that + // is newer than the most recent fetched one, as it delimits a section comprised of only + // items present in `newIds` (or that were deleted from the server, so should be removed + // anyway). + // Stop the gap *after* that item. + const firstIndex = oldIds.take(lastIndex).findLastIndex(id => id !== null && compareId(id, newIds.first()) > 0) + 1; + + // Make sure we aren't inserting duplicates + let insertedIds = ImmutableOrderedSet(newIds).subtract(oldIds.take(firstIndex), oldIds.skip(lastIndex)).toList(); + // Finally, insert a gap marker if the data is marked as partial by the server + if (isPartial && (firstIndex === 0 || oldIds.get(firstIndex - 1) !== null)) { + insertedIds = insertedIds.unshift(null); } - return oldIds.take(firstIndex + 1).concat( - isPartial && oldIds.get(firstIndex) !== null ? newIds.unshift(null) : newIds, + return oldIds.take(firstIndex).concat( + insertedIds, oldIds.skip(lastIndex), ); });