Math comparison operators don't combine if different

[LeaVerou]

I.e. while 1 < 2 < 3 is correctly interpreted as 1 < 2 and 2 < 3, this does not happen with -3 <= -3 < 1 which returns false, since it's interpreted as (-3 <= -3) < 1 => true < 1 => 1 < 1 = false

[betaveros]

The converse problem also occurs: identical comparison operators are chained even if explicit parentheses should prevent them from doing so. For example (5 > 4) > 3 is actually interpreted as chained 5 > 4 > 3, which is True.

I don't think we can make comparison operators chain properly if we only use jsep as-is because it throws away parenthesization information after parsing, so that (5 > 4) > 3 and 5 > 4 > 3 give identical parse results.

[LeaVerou]

Damn, that's right. Well spotted.
OTOH I'm not sure that's a significant problem for comparison operators. (5 > 4) is true, so then (5 > 4) > 3 would be true > 3 which is nonsensical to non-programmers who wouldn't think of true as 1.
Thankfully, it does not seem to occur with other operators, where it would be a real problem. For example 1 / (2 / 3) is correctly 1.5, and not 0.1666667 (1 / 2 / 3).