diff --git a/pages/fundamentals/storage-memory-usage.mdx b/pages/fundamentals/storage-memory-usage.mdx
index beadd1f8e..f19f403fe 100644
--- a/pages/fundamentals/storage-memory-usage.mdx
+++ b/pages/fundamentals/storage-memory-usage.mdx
@@ -489,8 +489,8 @@ Each `Delta` object has a least **56B**.
 
 {<h4> <code>Vertex</code> memory layout </h4>}
 
-Each `Vertex` object has at least **112B** + **56B** for the `Delta` object, in
-total, a minimum of **168B**.
+Each `Vertex` object has at least **88B** + **56B** for the `Delta` object, in
+total, a minimum of **144B**.
 
 Each additional label takes **4B**.
 
@@ -578,7 +578,7 @@ Let's assume the name on average has $3\text{B}+10\text{B} = 13\text{B}$ (each
 name is on average 10 characters long). One the average values are included, the
 calculation is:
 
-$19,148 \times (112\text{B} + 13\text{B} + 16\text{B} + 16\text{B} + 56\text{B}) = 19,148 \times 213\text{B} = 4,078,524\text{B}.$
+$19,148 \times (88\text{B} + 13\text{B} + 16\text{B} + 16\text{B} + 56\text{B}) = 19,148 \times 189\text{B} = 3,618,972\text{B}.$
 
 The remaining 2,584 vertices are the `ComicSeries` vertices with the `title` and
 `publishYear` properties. Let's assume that the `title` property is
@@ -590,9 +590,9 @@ list occupies $3 \times 2\text{B} \times 2\text{B} = 12\text{B}$. Using the same
 formula as above, but being careful to include both `title` and `publishYear`
 properties, the calculation is:
 
-$2584 \times (112\text{B} + 13\text{B} + 12\text{B} + 16\text{B} + 16\text{B} + 56\text{B}) = 2584 \times 225\text{B} = 581,400\text{B}.$
+$2584 \times (88\text{B} + 13\text{B} + 12\text{B} + 16\text{B} + 16\text{B} + 56\text{B}) = 2584 \times 201\text{B} = 519,384\text{B}.$
 
-In total, $4,659,924\text{B}$ to store vertices.
+In total, $4,138,356\text{B}$ to store vertices.
 
 The edges don't have any properties on them, so the formula is as follows:
 
@@ -626,7 +626,7 @@ $3 \times 21,723 \times (80\text{B}+13\text{B}+16\text{B})= 65,169 \times 109\te
 
 Now let's sum up everything we calculated:
 
-$4,659,924\text{B} + 87,416,704\text{B} + 2,606,760\text{B} + 7,103,421\text{B} = 101,786,809 \text{B} \approx 102\text{MB}.$
+$4,138,356\text{B} + 87,416,704\text{B} + 2,606,760\text{B} + 7,103,421\text{B} = 101,265,241 \text{B} \approx 99\text{MB}.$
 
 Bear in mind the number can vary because objects can have higher overhead due to
 the additional data.