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Workflows should print out help per default #1674

arokem opened this Issue Nov 29, 2018 · 1 comment


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arokem commented Nov 29, 2018

For example, when you type:


It would be much better if you got the help documentation than the current:

(dipy) code (master)$dipy_fit_dti 
Too few arguments: Program dipy_fit_dti expects arguments.

Type dipy_fit_dti -h for help.

Traceback (most recent call last):
  File "/Users/arokem/.virtualenvs/dipy/bin/dipy_fit_dti", line 7, in <module>
    exec(compile(, __file__, 'exec'))
  File "/Users/arokem/source/dipy/bin/dipy_fit_dti", line 9, in <module>
  File "/Users/arokem/source/dipy/dipy/workflows/", line 57, in run_flow
    args = parser.get_flow_args()
  File "/Users/arokem/source/dipy/dipy/workflows/", line 275, in get_flow_args
    ns_args = self.parse_args(args, namespace)
  File "/Users/arokem/source/dipy/dipy/fixes/", line 1667, in parse_args
    args, argv = self.parse_known_args(args, namespace)
  File "/Users/arokem/source/dipy/dipy/fixes/", line 1699, in parse_known_args
    return self._parse_known_args(args, namespace)
  File "/Users/arokem/source/dipy/dipy/fixes/", line 1917, in _parse_known_args
    self.error(_('too few arguments'))
UnboundLocalError: local variable '_' referenced before assignment

Which does include the instruction to use the -h flag, but is buried inside of a stack that is not super informative. Does anyone know how to make -h the default behavior in the absence of any other inputs?


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skoudoro commented Nov 29, 2018

I agree, thanks for this feedback. I just know that you need to call IntrospectiveArgumentParser.print_help() on file but I do not know how to avoid the Traceback yet. We need to look deeper into it...

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