Module-3

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3a : C program that function accepts two integers and find the sum of all numbers in range from 1 to m(both inclusive) that are not divisible by n. Return difference between sum of integers not divisible by n with sum of numbers divisible by n.

AIM:

To write a C program that function accepts two integers and find the sum of all numbers in range from 1 to m(both inclusive) that are not divisible by n. Return difference between sum of integers not divisible by n with sum of numbers divisible by n.

ALGORITHM:

1. Start
2. Read n and m
3. Set sum_div = 0, sum_not_div = 0
4. For each number i from 1 to m:

• If i % n == 0:
• Add i to sum_div
• Else:
• Add i to sum_not_div

5. Compute difference = sum_not_div - sum_div
6. Print difference
7. End

PROGRAM:

#include <stdio.h>
int check(int m, int n)
{
    int sum1 = 0, sum2 = 0;
    for (int i = 1; i <= m; i++)
    {
        if (i % n == 0)
            sum1 += i;
        else 
            sum2 += i;
    }
    return sum2 - sum1;
}
int main()
{
    int num1, num2, diff;
    scanf("%d %d", &num1, &num2);
    diff = check(num2, num1);
    printf("%d", diff);
    return 0;
}

OUTPUT:

RESULT:

Thus, the program has been executed successfully.

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3b : C program to check whether the given number is Armstrong number or not.

AIM:

To write a C program to check whether the given number is Armstrong number or not.

ALGORITHM:

1. Start
2. Read num
3. Set temp = num, sum = 0
4. While temp ≠ 0:

• Extract digit: digit = temp % 10
• Add cube of digit to sum
• Remove digit: temp = temp / 10

5. If sum == num:

• Print "Armstrong number"
• Else print "Not an Armstrong number"

6. End

PROGRAM:

#include <stdio.h>
int main()
{
    int num1, temp, arm, a = 0;
    scanf("%d", &num1);
    temp = num1;
    while (temp != 0)
    {
        a = temp % 10;
        arm += a*a*a;
        temp /= 10;
    }
    if (arm == num1)
        printf("%d is a armstrong number", num1);
    else 
        printf("%d is not a armstrong number", num1);
}

OUTPUT:

RESULT:

Thus, the program has been executed successfully.

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3c : C program to read n number of elements and check whether the second element is odd or even.

AIM:

To write a C program to read n number of elements and check whether the second element is odd or even.

ALGORITHM:

1. Start
2. Read n
3. Read n elements into array a
4. If a[1] % 2 ≠ 0:

• Print "Second element is odd"

5. Else:

• Print "Second element is even"

6. End

PROGRAM:

#include <stdio.h>
int main()
{
    int n;
    scanf("%d",&n);
    int a[n];
    for(int i=0;i<n;i++)
    {
        scanf("%d",&a[i]);
    }
    if(a[1]%2!=0)
        printf("The second element %d is an odd number" ,a[1]);
    else
        printf("The second element %d is an even number", a[1]);
}

OUTPUT:

RESULT:

Thus, the program has been executed successfully.

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3d : C Program to Print the count of odd Numbers in an Array

AIM:

To write a C Program to Print the count of odd Numbers in an Array

ALGORITHM:

1. Start
2. Read n
3. Initialize odd_count = 0, even_count = 0
4. Repeat n times:

• Read a number
• If number is divisible by 2:
• Increment even_count
• Else:
• Increment odd_count

5. Print odd_count
6. End

PROGRAM:

#include<stdio.h>
int main()
{
   int a[100], n, i, ecount=0, ocount=0;
   scanf("%d",&n);
   for(i=0; i<n; i++)
   {
        scanf("%d",&a[i]);
        if(a[i]%2==0) 
            ecount ++;
        else 
            ocount++;
   }
   printf("Odd numbers: %d",ocount);
   return 0;
}

OUTPUT:

RESULT:

Thus, the program has been executed successfully.

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3e : C program to generate the Fibonacci series for the given input using do-while loop.

AIM:

To write a C program to generate the Fibonacci series for the given input using do-while loop.

ALGORITHM:

1. Start
2. Read n
3. Initialize f1 = -1, f2 = 1
4. Repeat n times:

• Compute f3 = f1 + f2
• Print f3
• Update f1 = f2, f2 = f3

5. End

PROGRAM:

#include <stdio.h>
int main()
{
    int num1, f1 = -1, f2 = 1, f3 = 0;
    scanf("%d", &num1);
    for (int i = 1 ; i <= num1; i++)
    {
        f3 = f1 + f2;
        printf("%d ", f3);
        f1 = f2;
        f2 = f3;
    }
    return 0;
}

OUTPUT:

RESULT:

Thus, the program has been executed successfully.

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