Skip to content

HTTPS clone URL

Subversion checkout URL

You can clone with
or
.
Download ZIP
Django social authentication made simple
Python HTML Makefile

Fetching latest commit…

Cannot retrieve the latest commit at this time

Failed to load latest commit information.
contrib
doc
example
social_auth
.gitignore
COPYRIGHT.django-twitter-oauth
ChangeLog
LICENSE
LICENSE.django-openid-auth
Makefile
README.rst
django-social-auth.spec
requirements.txt
setup.py

README.rst

Django Social Auth

Django Social Auth is an easy way to setup social authentication/authorization mechanism for Django projects.

Crafted using base code from django-twitter-oauth and django-openid-auth, it implements a common interface to define new authentication providers from third parties.

You can view this app's documentation on Read the Docs too.

Demo

There's a demo at http://social.matiasaguirre.net/. Note: It lacks some backends' support at the moment.

Features

This application provides user registration and login using social site credentials. Some features are:

Documentation

Extensive documentaion at Read the Docs.

Dependencies

Dependencies that must be met to use the application:

Installation

From pypi:

$ pip install django-social-auth

or:

$ easy_install django-social-auth

or clone from github:

$ git clone git://github.com/omab/django-social-auth.git

and add social_auth to PYTHONPATH:

$ export PYTHONPATH=$PYTHONPATH:$(pwd)/django-social-auth/

or:

$ cd django-social-auth
$ sudo python setup.py install

Copyrights and Licence

django-social-auth is protected by BSD licence.

Some bits were derived from others' work and copyrighted by:

  • django-twitter-oauth:

    Original Copyright goes to Henrik Lied (henriklied)
    Code borrowed from https://github.com/henriklied/django-twitter-oauth
    
  • django-openid-auth:

    django-openid-auth -  OpenID integration for django.contrib.auth
    Copyright (C) 2007 Simon Willison
    Copyright (C) 2008-2010 Canonical Ltd.
    
Something went wrong with that request. Please try again.