Reasoning and answer: 300m is a quarter of the distance from the riverbed to the hill's peak so (1 / 4) * distance from riverbed to peak = 300m. Multiplying both sides of the equation by 4 gives the distance from riverbed to peak = 300m * 4 = 1200m. The height of the hill is the difference between the distance from the riverbed to the hill's peak and the distance from the riverbed to the hill's base which is 1200m - 300m = 900m.
The answer: 900
What was the question?
Question: The base of a hill located beside a river is 300m above the seabed. If this depth is a quarter of the vertical distance between the riverbed and the peak of the hill, how high is the hill?


Currently, the farm has 2 + 3 + 6 = 11 animals. The farmer will add 3 + 5 + 2 = 10 animals. So, the farm will have 11 + 10 = 21 animals.
The answer: 21
Reverse engineering the question: On a farm, there are 2 cows, 3 pigs, and 6 goats. The farmer planned on adding 3 cows, 5 pigs, and 2 goats. How many animals will there be on the farm?


Reasoning and answer: He buys 3 * 100 = 300m. So he gets 300 / 10 = 30 sections.
The answer: 30
What was the question?
Question: John buys 3 reels of 100m fishing line. He cuts it into 10m sections. How many sections does he get?


There are 60 minutes in an hour so 1 hour 20 minutes = (60 + 20) minutes = 80 minutes. He will spend a total of 80 + 10 = 90 minutes. 90 minutes is = (60 / 60) hours and 30 minutes = 1 hour 30 minutes = 0130 in 24 - hr time. He has to leave 0130 hours earlier than 0900 i.e. 0900 - 0130 = 0730 hours.
The answer: 730
Reverse engineering the question: Pete has to take a 10-minute walk down to the train station and then board a 1hr 20-minute train to LA. When should he leave if he cannot get to LA later than 0900 hours? (24-hr time)


Reasoning and answer: First find how many demerits Andy got for showing up late: 2 demerits / time * 6 times = 12 demerits. Then subtract the number of demerits he's gotten so far to find how many more he can get before getting fired: 50 demerits - 12 demerits - 15 demerits = 23 demerits.
The answer: 23
What was the question?
Question: Andy can get 50 demerits in a month before getting fired. If he got 2 demerits per instance for showing up late 6 times and 15 demerits for making an inappropriate joke, how many more demerits can he get this month before getting fired?


Reasoning and answer: Jar B has 28 + 12 = 40 marbles. Jar C has 2 x 40 = 80 marbles. Therefore, there are 28 + 40 + 80 = 148 marbles altogether.
The answer: 148
What was the question?
Question:
Jar A has 28 marbles. Jar B has 12 more marbles than jar A. Jar C has twice as many marbles as jar B. How many marbles are there altogether?