Q: Jonsey is awake for 2/3 of the day and spends 1/2 her time awake playing outside and the rest inside. Her brother, Riley, is awake for 3/4 of the day and spends 1/3 of his day outside and the rest inside. How much time, on average, do they spend inside?
A: Jonsey is awake for 16 hours because 24 x (2 / 3) = 16. Jonsey spends 1 / 2 her day inside because 1 - (1 / 2) = 1 / 2. Jonsey spend 8 hours inside because 16 x (1 / 2) = 8. Riley is awake for 18 hours because 24 x (3 / 4) = 18. Riley spends 2 / 3 of his day inside because 1 - (1 / 3) = 2 / 3. Riley spends 12 hours inside because 18 x (2 / 3) = 12. In total they spend 20 hours inside because 8 + 12 = 20. On average, they spend 10 hours inside because 20 / 2 = 10. The answer is 10.

Q: Mr. Ha owns 5 more silver dollars than Mr. Phung. Mr. Phung has 16 more silver dollars than Mr. Chiu has. If Mr. Chiu has 56 silver dollars, how many silver dollars the three have in total?
A: Mr. Chiu has 56 silver dollars. If Mr. Phung has 16 more silver dollars than Mr. Chiu, then his total silver dollars is 56 + 16 = 72. The total number of silver dollars that Mr. Ha owns is 72 + 5 = 77. Combined, together they have 77 + 72 + 56 = 205 silver dollars. The answer is 205.

Q: Jason spent 1/4 of his money and an additional $10 on some books. He then spent 2/5 of the remaining money and an additional $8 on some DVDs. If he was left with $130, how much money did he have at first?
A:
Let X be the money Jason had at first. Jason spent 1 / 4 * X + 10 on books. Jason spent 2 / 5 * [X - (1 / 4 * X + 10)] + 8 on some DVDs. Jason has X - (1 / 4 * X + 10) - {2 / 5 * [X - (1 / 4 * X + 10)] + 8} = $130 left. X - 1 / 4 * X - 10 - 2 / 5 * X + 1 / 10 * X + 4 - 8 = $130. 9 / 20 * X - 14 = $130. X = $320. The answer is 320.