[Question]The base of a hill located beside a river is 300m above the seabed. If this depth is a quarter of the vertical distance between the riverbed and the peak of the hill, how high is the hill?
[Answer]300m is a quarter of the distance from the riverbed to the hill's peak so (1 / 4) * distance from riverbed to peak = 300m. Multiplying both sides of the equation by 4 gives the distance from riverbed to peak = 300m * 4 = 1200m. The height of the hill is the difference between the distance from the riverbed to the hill's peak and the distance from the riverbed to the hill's base which is 1200m - 300m = 900m. The answer is 900.
Q: On a farm, there are 2 cows, 3 pigs, and 6 goats. The farmer planned on adding 3 cows, 5 pigs, and 2 goats. How many animals will there be on the farm?
A: Currently, the farm has 2 + 3 + 6 = 11 animals. The farmer will add 3 + 5 + 2 = 10 animals. So, the farm will have 11 + 10 = 21 animals. The answer is 21.
Question: John buys 3 reels of 100m fishing line. He cuts it into 10m sections. How many sections does he get?
Answer: He buys 3 * 100 = 300m. So he gets 300 / 10 = 30 sections. The answer is 30.
[Question]Pete has to take a 10-minute walk down to the train station and then board a 1hr 20-minute train to LA. When should he leave if he cannot get to LA later than 0900 hours? (24-hr time)
[Answer]There are 60 minutes in an hour so 1 hour 20 minutes = (60 + 20) minutes = 80 minutes. He will spend a total of 80 + 10 = 90 minutes. 90 minutes is = (60 / 60) hours and 30 minutes = 1 hour 30 minutes = 0130 in 24 - hr time. He has to leave 0130 hours earlier than 0900 i.e. 0900 - 0130 = 0730 hours. The answer is 730.
Q: Andy can get 50 demerits in a month before getting fired. If he got 2 demerits per instance for showing up late 6 times and 15 demerits for making an inappropriate joke, how many more demerits can he get this month before getting fired?
A: First find how many demerits Andy got for showing up late: 2 demerits / time * 6 times = 12 demerits. Then subtract the number of demerits he's gotten so far to find how many more he can get before getting fired: 50 demerits - 12 demerits - 15 demerits = 23 demerits. The answer is 23.
Question: Jar A has 28 marbles. Jar B has 12 more marbles than jar A. Jar C has twice as many marbles as jar B. How many marbles are there altogether?
Answer:
Jar B has 28 + 12 = 40 marbles. Jar C has 2 x 40 = 80 marbles. Therefore, there are 28 + 40 + 80 = 148 marbles altogether. The answer is 148.