Q: There are 100 jellybeans in a glass jar. Mrs. Copper’s kindergarten class normally has 24 kids, but 2 children called in sick and stayed home that day. The remaining children who attended school eat 3 jellybeans each. How many jellybeans are still left in the jar?
A: With the sick children who stayed home, there are this many kindergarten students in the class: 24 - 2 = 22 kids. This many jellybeans are eaten: 22 x 3 = 66 jellybeans. This many jellybeans are still left in the jar: 100 - 66 = 34 jellybeans. The answer is 34.

Q: Julia collects old watches. She owns 20 silver watches, and three times as many bronze watches. She decided to buy gold watches to add to her collection, a number that represents 10% of all the watches she owns. How many watches does Julia own after this purchase?
A: Julia owns 3 * 20 = 60 bronze watches. 60 + 20 = 80 total silver and bronze watches. 10% of all Julia's watches is 80 * 10 / 100 = 8 watches, and she decided to buy so many gold watches. So in total Julia is in possession of 20 + 60 + 8 = 88 watches. The answer is 88.

Q: Vermont opened up 4 web pages on his web browser and found 12 ads on the first web page and twice as many ads on the second web page as the first web page. When he opened the third web page, he found 24 more ads than the number of ads on the second web page. If the fourth web page had 3/4 times as many ads as the second web page, calculate the total number of ads Vermont clicked on if he clicked on 2/3 of them.
A:
If Vermont found 12 ads on the first web page and twice as many ads on the second web page as the first web page, he found 12 * 2 = 24 ads on the second web page. The first and the second web page had a total of 12 + 24 = 36. Vermont also found 24 more ads on the third web page than the second web page, a total of 24 + 24 = 48 ads. The first three web pages had 48 + 36 = 84 ads. The fourth web page had 3 / 4 times as many ads as the second web page, a total of 3 / 4 * 24 = 18 ads. In all the web pages Vermont opened, he found 84 + 18 = 102 ads. If he clicked on 2 / 3 of them, he clicked on 2 / 3 * 102 = 68 ads. The answer is 68.