Q: A captain steers his ship 100 miles north on the first day of their journey. On the second day, he sails to the east three times as far as the distance as he covered on the first day. On the third day, the ship travels further east for 110 more miles than the distance it covered on the second day. What is the total distance the ship has traveled in the three days?
A: 810
Explain how we arrive at this answer:
Explanation: If the ship traveled 100 miles to the north, it sailed for a distance of 3 * 100 miles = 300 miles to the east on the second day. On the third day, the sheep sailed for 300 miles + 110 miles = 410 miles. The distance covered by the ship in the three days is 410 miles + 300 miles + 100 miles = 810 miles.