Sweet Hope hosts a casino with 3 roulette tables labeled A, B, and C. At 6:00 pm, Table B had twice as much money on it as table C, which had $20 more than table A. If there was $40 on table A, how much money was there on all the tables? Let's be accurate as possible.
If table C had $20 more than table A, then table C had $20 + $40 = $60. Roulette tables A and C had $60 + $40 = $100. Table B had twice as much money on it as table C, meaning table B had $60 * 2 = $120. Together, the three roulette tables had $120 + $100 = $220.
The answer: 220.