Q: In Dana's senior high school class there were 200 students. 60% of the students were female, and 50% of the females were brunettes. If 50% of the female brunettes were under 5 feet tall, then how many female brunettes in Dana's high school senior class were under 5 feet tall?
A: In Dana's senior class, the 60% of 200 students is 0.6 * 200 = 120 female students. Fifty percent of the females, or 0.5 * 120 = 60 of the female students were brunettes. If 50% of the female brunettes were under 5 feet tall, then there were 60 * 0.5 = 30 female brunettes under five feet tall in Dana's senior class. The answer is 30.
Question: A school is buying virus protection software to cover 50 devices. One software package costs $40 and covers up to 5 devices. The other software package costs $60 and covers up to 10 devices. How much money, in dollars, can the school save by buying the $60 software package instead of the $40 software package?
Answer: There are 50 / 5 = 10 sets of 5 devices in the school. So the school will pay a total of $40 x 10 = $400 for the $40 software package. There are 50 / 10 = 5 sets of 10 devices in the school. So the school will pay a total of $60 x 5 = $300 for the $60 software package. Thus, the school can save $400 - $100 = $300 from buying the $60 software instead of the $40 software package. The answer is 100.
[Question]Terry drives at a speed of 40 miles per hour. He drives daily forth and back from his home to his workplace which is 60 miles away from his home. How many hours does Terry spend driving from home to the workplace and then back?
[Answer]The miles that Terry drives daily from home and back are 60 * 2 = 120 miles. The hours he takes driving from home and back are 120 / 40 = 3 hours. The answer is 3.
Q: Cheryl ate 7 m&m's after lunch. She ate 5 m&m's after dinner, and she gave some to her sister. If Cheryl had 25 m&m's at the beginning, how many did she give to her sister?
A: Cheryl at 7 + 5 = 12 m&m's. She gave 25 - 12 = 13 m&m's to her sister. The answer is 13.
Question: Georgie is a varsity player on a football team. He can run 40 yards within 5 seconds. If he can improve his speed by forty percent, how many yards will he be able to run within 10 seconds?
Answer: The additional yard he will be able to run to after improving his speed is 40 x 40 / 100 = 16 yards. So the total yard he will be able to run to after improving his speed is 40 + 16 = 56 yards in 5 seconds. Therefore the total yards he will be able to run to within 10 seconds is 56 x 2 = 112. The answer is 112.
Q: James decides to build a tin house by collecting 500 tins in a week. On the first day, he collects 50 tins. On the second day, he manages to collect 3 times that number. On the third day, he collects 50 tins fewer than the number he collected on the second day. If he collects an equal number of tins on the remaining days of the week, what's the number of tins he collected each day for the rest of the week?
A:
On the second day, he collected 3 times the number of tins he collected on the first day, which is 3 * 50 = 150 tins. On the third day, he collected 50 tins fewer than the second day, which is 150 - 50 = 100 tins. The total for the three days is 150 + 100 + 50 = 300 tins. To reach his goal, he still needs 500 - 300 = 200 tins. Since the total number of days left in the week is 4, he'll need to collect 200 / 4 = 50 tins per day to reach his goal. The answer is 50.