A family of 12 monkeys collected 10 piles of bananas. 6 piles had 9 hands, with each hand having 14 bananas, while the remaining piles had 12 hands, with each hand having 9 bananas. How many bananas would each monkey get if they divide the bananas equally amongst themselves? Let's be accurate as possible.
The first 6 bunches had 6 x 9 x 14 = 756 bananas. There were 10 - 6 = 4 remaining bunches. The 4 remaining bunches had 4 x 12 x 9 = 432 bananas. All together, there were 756 + 432 = 1188 bananas. Each monkey would get 1188 / 12 = 99 bananas.
The answer: 99.