Lizzy: A coach placed 15 tennis balls and 5 soccer balls each into 5 baskets. He gave 5 of his students a short period of time to remove as many balls each from a basket as they could. 3 of them removed 8 balls each and the other 2 removed a certain number of balls each. If a total of 56 balls are still in the baskets, how many balls did the other 2 students each remove?.
Me: Hmmm, let me think. I think this is the detailed solution:
Combining the tennis and soccer balls, there are 15 + 5 = 20 balls in each basket. There are 5 baskets, hence 5 * 20 = 100 balls in total. 3 students removed 8 balls each, they removed 3 * 8 = 24 balls. From the total number of balls, they left 100 - 24 = 76 balls. There are 56 balls left so the other 2 students must have removed a total of 76 - 56 = 20 balls. This means that each of these 2 students removed 20 / 2 = 10 balls. Final answer: 10.