Come up with a question and reasoning that would justify [120] as the answer.
The question is: Marites internet speed is 10 megabits per second and her monthly internet bill is $20. Marites is planning to upgrade her service and choosing between 20 Mbps and 30 Mbps. If the price of the 30 Mbps is twice the amount of her current monthly bill and the price of the 20 Mbps is $10 more than her current monthly bill, how much will she save per year if she chooses the 20 Mbps than 30 Mbps?
Reasoning: The total monthly bill for 30 Mbps is $20 x 2 = $40. She will have to pay $40 x 12 = $480 every year for 30mbps. The total monthly bill for 20 Mbps is $20 + $10 = $30. So, she will have to pay $30 x 12 = $360 for 20 Mbps per year. Therefore the amount she will save per year if she chooses the 20mbps is $480 - $360 = $120.

Come up with a question and reasoning that would justify [7] as the answer.
The question is: On a four-day trip, Carrie drove 135 miles the first day, 124 miles more the second day, 159 miles the third day, and 189 miles the fourth day. If she had to charge her phone every 106 miles, how many times did she charge her phone for the whole trip?
Reasoning: Carrie drove 135 + 124 = 259 miles on the second day. Carrie drove 135 + 259 + 159 + 189 = 742 miles for the whole trip. Carries charged her phone 742 / 106 = 7 times.

Come up with a question and reasoning that would justify [247] as the answer.
The question is: There is three less than four times the number of students in Elementary School as there are in Middle School. If the number of students in Middle school is 50, calculate the total number of students in both levels.
Reasoning: The number of students in elementary school is three less than four times the number in middle school: 4 * 50 students = 200 students. This means that there are 200 students - 3 students = 197 students in Elementary school. The total number of students in both levels is 197 students + 50 students = 247 students.