Q: Vermont opened up 4 web pages on his web browser and found 12 ads on the first web page and twice as many ads on the second web page as the first web page. When he opened the third web page, he found 24 more ads than the number of ads on the second web page. If the fourth web page had 3/4 times as many ads as the second web page, calculate the total number of ads Vermont clicked on if he clicked on 2/3 of them.
A: If Vermont found 12 ads on the first web page and twice as many ads on the second web page as the first web page, he found 12 * 2 = 24 ads on the second web page. The first and the second web page had a total of 12 + 24 = 36. Vermont also found 24 more ads on the third web page than the second web page, a total of 24 + 24 = 48 ads. The first three web pages had 48 + 36 = 84 ads. The fourth web page had 3 / 4 times as many ads as the second web page, a total of 3 / 4 * 24 = 18 ads. In all the web pages Vermont opened, he found 84 + 18 = 102 ads. If he clicked on 2 / 3 of them, he clicked on 2 / 3 * 102 = 68 ads. The answer is 68.
Question: On a Sunday morning, Josephine sold milk in the farm stall. The buyers brought their containers. She filled three containers with two liters each, two containers with 0.75 liters each, and five containers with 0.5 liters each. How many liters of milk did Josephine sell in total?
Answer: Josephine filled a total of 2 x 3 = 6 liters from the three containers with two liters each. She filled a total of 0.75 x 2 = 1.5 liters from the two containers with 0.75 liters each. She filled a total of 0.5 x 5 = 2.5 liters from the five containers with 0.5 liters each. Therefore, she sold a total of 6 + 1.5 + 2.5 = 10 liters of milk. The answer is 10.
[Question]Two alien spacecraft on a sightseeing tour of Earth left New Orleans airport at 3:00 pm to travel the 448-mile distance to Dallas by air. Traveling nonstop, the first spacecraft landed in Dallas at 3:30 pm, while the second spacecraft landed in Dallas thirty minutes later. Assuming both spacecraft traveled at constant speed, what was the difference in speed, in miles per hour, between the two spacecraft?
[Answer]The first spacecraft flew for 30 minutes, or 30 / 60 = 1 / 2 hour. The second spacecraft flew for 30 + 30 = 60 minutes, or 1 hour. Thus the first spacecraft traveled at a speed of 448 miles in 1 / 2 hour, or 448 / (1 / 2) = 896 miles per hour. The second spacecraft traveled 448 miles in 1 hour, or 448 / 1 = 448 miles per hour. The difference in speed, in miles per hour, between the two spacecraft was 896 - 448 = 448 miles per hour. The answer is 448.
Q: Rachel solved 5 math problems each minute for 12 minutes before bed, but she didn't finish all of them. The next day, she finished the last 16 problems at lunch. How many math problems did she do in all?
A: Before going to bed, Rachel did a total of 5 × 12 = 60 problems. In total Rachel did 60 + 16 = 76 maths problems. The answer is 76.
Question: If 100 pieces, each 15 centimeters long, are cut from a 51-meter long ribbon, how much ribbon remains ?
Answer: The total length cut from the 51 - meter ribbon is 100 x 15 centimeters = 1500 centimeters. Since 1 meter is equal to 100 centimeters, then 1500 centimeters is equal to 1500 / 100 = 15 meters. Therefore, 51 - 15 = 36 meters of ribbon remains. The answer is 36.
Q: Kathleen receives a weekly allowance for completing all of her chores. During middle school, her allowance was $2 more than $8 but during her senior year, her allowance was $5 more than twice her middle school allowance. What is the percentage increase in Kathleen's weekly allowance?
A:
Kathleen's allowance in middle school was $8 + $2 = $10. Twice her middle school allowance is $10 x 2 = $20. So, Kathleen's senior year allowance is $20 + $5 = $25. Her allowance increased by $25 - $10 = $15. Kathleen's percent increase in her weekly allowance is $15 / $10 x 100% = 150%. The answer is 150.