Ronald is rolling a die and won't stop rolling until the average of all his rolls is a 3. He rolls a 1, a 3, a 2, a 4, a 3, a 5, a 3, a 4, a 4 and a 2. What does he need to roll on the next roll to be able to stop? Give me reasons, before answering the question
The next roll will be his 11th roll. The total on this tenth roll to have an average of 3 is 33, because 3 * 11 = 33. His current total is 31 because 1 + 3 + 2 + 4 + 3 + 5 + 6 + 1 + 4 + 2 = 31. He needs to roll a 2 because 33 - 31 = 2. So the final answer is 2.