Lizzy: Yuko likes to play board games. He decides to play a game with his brother Yuri. They must roll 3 dice at the same time and move the squares corresponding to the value of the 3 dice. Yuri started and his dice had the following combination: 2, 4, and 5. On Yuko's turn, he rolled 1, 5, and X. How many squares must Yuko's last die move him so that he is in front of his brother?.
Me: Hmmm, let me think. I think this is the detailed solution:
The sum of Yuri's dice gave, 2 + 4 + 5 = 11 squares. For Yuko to get the same sum in the dice, 1 + 5 + X = 11 squares. Solving the equation, X = 11 - 6, X = 5 squares. To stand in front of his brother, Yuko needs to be at least 1 place in front, so his last die will move him, 5 + 1 = 6 squares. Final answer: 6.