Question: Christine and Janice are having a contest to see who can throw a ball the highest. They each get three throws. On her first throw, Christine throws it 20 feet high. Janice's throw is 4 feet lower than Christine's. On their second throw, Christine throws it ten feet higher than her first throw and Janice throws it twice as high as her first throw. On the final throw, Christine throws it 4 feet higher than her 2nd throw while Janice throws it 17 feet higher than Christine's first throw. What is the height of the highest throw? Think carefully first, then make a decision:
We know Christine's second throw was 30 feet high because 20 + 10 = 30. We know Christine's third throw was 34 feet because 30 + 4 = 34. Janice's first throw was 16 feet because 20 - 4 = 16. Janice's second throw was 32 feet because 16 * 2 = 32. Janice's final throw was 37 feet high because 20 + 17 = 37. The six throws were 20 feet, 30 feet, 34 feet, 16 feet, 32 feet, and 37 feet, and of these numbers, 37 feet was the highest. So the answer is 37.