Q: Jane, Kyla, and Anthony have summer jobs in a resort. Their task is to fold guests' towels. Jane can fold 3 towels in 5 minutes. Kyla can fold 5 towels in 10 minutes, and Anthony can fold 7 towels in 20 minutes. If they all fold towels together, how many towels can they fold in one hour?
A: There are 1 x 60 minutes = 60 minutes in 1 hour. There are 60 / 5 = 12 sets of 5 minutes in 1 hour. So, Jane can fold 3 x 12 = 36 towels in an hour. There are 60 / 10 = 6 sets of 10 minutes in 1 hour. So, Kyla can fold 5 x 6 = 30 towels in an hour. There are 60 / 20 = 3 sets of 20 minutes in 1 hour. So, Anthony can fold 7 x 3 = 21 towels in an hour. Therefore, the 3 of them can fold a total of 36 + 30 + 21 = 87 towels in 1 hour. The answer is 87.

Q: Bob can shuck 10 oysters in 5 minutes. How many oysters can he shuck in 2 hours?
A: He shucks 10 oysters in 5 minutes we need to know how many 5 minute units are in 60 minutes so 60 / 5 = 12 units. He can shuck 10 oysters in 5 minutes and there are 12 5 minute units in an hour so he can shuck 10 * 12 = 120 oysters in 1 hour. If he can shuck 120 oysters in 1 hour, so for 2 hours in can shuck 2 * 120 = 240 oysters. The answer is 240.

Q: Sam and Jeff had a skipping competition at recess. The competition was split into four rounds. Sam completed 1 more skip than Jeff in the first round. Jeff skipped 3 fewer times than Sam in the second round. Jeff skipped 4 more times than Sam in the third round. Jeff got tired and only completed half the number of skips as Sam in the last round. If Sam skipped 16 times in each round, what is the average number of skips per round completed by Jeff?
A:
In round one, Jeff completed 16 - 1 = 15. In round two, Jeff completed 16 - 3 = 13. In round three, Jeff completed 16 + 4 = 20. In round four, Jeff completed 16 / 2 = 8. Jeff completed 15 + 13 + 20 + 8 = 56 skips in total. Jeff skipped an average of 56 / 4 = 14 skips per round. The answer is 14.