Q: Carson is going to spend 4 hours at a carnival. The wait for the roller coaster is 30 minutes, the wait for the tilt-a-whirl is 60 minutes, and the wait for the giant slide is 15 minutes. If Carson rides the roller coaster 4 times and the tilt-a-whirl once, how many times can he ride the giant slide? (Wait times include the time actually spent on the ride.)
A: First figure out how many minutes Carson spends at the carnival by multiplying the number of hours he's there by the number of minutes per hour: 4 hours * 60 minutes / hour = 240 minutes. Then figure out how long Carson spends waiting for the roller coaster by multiplying the wait time per ride by the number of rides: 4 rides * 30 minutes / ride = 120 minutes. Now subtract the time Carson spends on the roller coaster and tilt - a - whirl from the total time he spends at the park to find out how much time he has left: 240 minutes - 120 minutes - 60 minutes = 60 minutes. Now divide the time Carson has left by the wait time for the giant slide to see how many times he can ride it: 60 minutes / 15 minutes / ride = 4 rides. The answer is 4.
Question: Thomas started saving for a car almost 2 years ago. For the first year, his weekly allowance was $50. In the second year, he got a job that pays $9 an hour at a coffee shop and worked 30 hours a week, so his parents discontinued his allowance. If the car he wants to buy is $15,000 and he spends $35 a week on himself, how much more money does Thomas need to buy the car by the end of the 2 years?
Answer: There are 52 weeks in a year. For the first year, Thomas received 52 x 50 = $2600. In the second year, Thomas earned 9 x 30 = $270 a week. In a year, Thomas earned 52 x 270 = $14,040. The total for the two years is 14040 + 2600 = 16640. In 2 years, Thomas' weekly expenses amounted to $35 x (52 x 2) = $35 x 104 = $3640. By the end of 2 years, Thomas would have saved $16640 - $3640 = 13000. Thomas still needs $15,000 - 13000 = $2000. The answer is 2000.
[Question]John decides to buy utensils. They come in 30 packs with an equal number of knives, forks, and spoons. How many packs does he need to buy if he wants 50 spoons?
[Answer]Each pack contains 30 / 3 = 10 spoons. So he needs to buy 50 / 10 = 5 packs. The answer is 5.
Q: The card shop has two boxes of cards. The first box contains cards that cost $1.25 each. The second box contains cards that cost $1.75 each. A boy then comes in and buys 6 cards from each box. What was the total cost, in dollars, of the cards he bought?
A: The cost of one card from each box in total is 1.25 + 1.75 = 3 dollars. The total cost of cards the boy bought is 3 * 6 = 18 dollars. The answer is 18.
Question: Vincent’s washer broke so he had to go to the laundromat. On Wednesday he washed six loads of clothes. The next day he had time to wash double the number of loads he did the day before. On Friday he had a test and could only manage half of the loads he did on Thursday. On Saturday the laundromat closed at noon and he could only wash a third of the loads of laundry he did on Wednesday. How many loads of laundry had he washed that week?
Answer: On Thursday he washed 6 * 2 = 12 loads of laundry. On Friday he washed 12 / 2 = 6 loads of laundry. On Saturday he washed 6 / 3 = 2 loads of laundry. In total he washed 6 + 12 + 6 + 2 = 26 loads of laundry. The answer is 26.
Q: Billy is counting the rings in two trees. Weather fluctuations in this area mean that each tree's rings are in groups of two fat rings and four thin rings. If Billy counts 70 ring groups in the first tree and 40 ring groups in the second tree, how much older is the first tree? (Trees grow 1 ring per year.)
A:
First find the total number of rings in a ring group: 2 rings + 4 rings = 6 rings. Then subtract the number of ring groups in the second tree from the number in the first tree to find the difference: 70 groups - 40 groups = 30 groups. Then multiply that number by the number of rings in a group to find the difference in the trees' ages: 30 groups * 6 rings / group = 180 rings, or 180 years. The answer is 180.