An aquarium holds an equal number of clownfish and blowfish. 26 of the blowfish stay in their own tank, and the remaining blowfish swim into a display tank. An equal number of clownfish join the blowfish in the display tank, but then a third of these clownfish swim back into their own tank. If the aquarium holds a combined total of 100 fish, how many clownfish are now in the display tank?
Thoughts? Step-by-step reasoning:
There is an equal number of clownfish and blowfish, which means there are 100 fish / 2 = 50 blowfish. Since some stay in their tanks, there are 50 blowfish – 26 blowfish = 24 blowfish in the display tank. There were the same amount of clownfish until 24 clownfish / 3 = 8 clownfish swam back to their own tank. This leaves 24 clownfish – 8 clownfish = 16 clownfish in the display tank.
Thus, the answer is 16.