# openset / leetcode Fetching latest commit…
Cannot retrieve the latest commit at this time.
Type Name Latest commit message Commit time
..
Failed to load latest commit information. README.md find_pivot_index.go find_pivot_index_test.go

## 724. Find Pivot Index (Easy)

Given an array of integers `nums`, write a method that returns the "pivot" index of this array.

We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of the index.

If no such index exists, we should return -1. If there are multiple pivot indexes, you should return the left-most pivot index.

Example 1:

```Input:
nums = [1, 7, 3, 6, 5, 6]
Output: 3
Explanation:
The sum of the numbers to the left of index 3 (nums = 6) is equal to the sum of numbers to the right of index 3.
Also, 3 is the first index where this occurs.
```

Example 2:

```Input:
nums = [1, 2, 3]
Output: -1
Explanation:
There is no index that satisfies the conditions in the problem statement.
```

Note:

• The length of `nums` will be in the range `[0, 10000]`.
• Each element `nums[i]` will be an integer in the range `[-1000, 1000]`.

[Array]

### Similar Questions

1. Subarray Sum Equals K (Medium)

### Hints

Hint 1 We can precompute prefix sums P[i] = nums + nums + ... + nums[i-1]. Then for each index, the left sum is P[i], and the right sum is P[P.length - 1] - P[i] - nums[i].
You can’t perform that action at this time.