{"payload":{"pageCount":1,"repositories":[{"type":"Public","name":"1-in-2-Probability-Executor-in-Node.js","owner":"Math-Engine","isFork":false,"description":"GitHub Actions를 사용하여 Node.js에서 1/2 확률을 계속해서 실행합니다.","allTopics":["probability"],"primaryLanguage":{"name":"JavaScript","color":"#f1e05a"},"pullRequestCount":0,"issueCount":0,"starsCount":1,"forksCount":0,"license":null,"participation":null,"lastUpdated":{"hasBeenPushedTo":true,"timestamp":"2024-07-15T22:28:21.772Z"}},{"type":"Public","name":"Faster-Finding-Collatz-Conjectural-Counterexamples","owner":"Math-Engine","isFork":true,"description":"GitHub Actions를 사용하여 콜라츠 추측 반례를 찾는 코드입니다. 이 코드는 안정적이지 않을 수도 있습니다.","allTopics":["collatz-conjecture"],"primaryLanguage":{"name":"JavaScript","color":"#f1e05a"},"pullRequestCount":0,"issueCount":0,"starsCount":0,"forksCount":1,"license":null,"participation":null,"lastUpdated":{"hasBeenPushedTo":true,"timestamp":"2024-07-15T22:27:53.427Z"}},{"type":"Public","name":"Finding-Collatz-Conjectural-Counterexamples","owner":"Math-Engine","isFork":false,"description":"GitHub Actions를 사용하여 콜라츠 추측 반례를 찾는 코드입니다.","allTopics":["collatz-conjecture"],"primaryLanguage":{"name":"JavaScript","color":"#f1e05a"},"pullRequestCount":0,"issueCount":0,"starsCount":1,"forksCount":1,"license":null,"participation":null,"lastUpdated":{"hasBeenPushedTo":true,"timestamp":"2024-07-15T22:26:41.427Z"}},{"type":"Public","name":"Find-Collatz-Conjecture-Counterexamples-from-2-to-the-68th-power","owner":"Math-Engine","isFork":false,"description":"GitHub Actions를 사용하여 2^68부터 콜라츠 추측 반례를 찾습니다.","allTopics":["collatz-conjecture"],"primaryLanguage":{"name":"JavaScript","color":"#f1e05a"},"pullRequestCount":0,"issueCount":0,"starsCount":0,"forksCount":0,"license":null,"participation":null,"lastUpdated":{"hasBeenPushedTo":true,"timestamp":"2024-07-15T22:25:12.891Z"}},{"type":"Public template","name":"TestRun-1-Mystic-ov-26-with-Python","owner":"Math-Engine","isFork":false,"description":"TestRun 1 - GitHub Actions를 사용하여 a^c - b^d = 2 를 만족하는 a, b, c, d 값을 찾습니다. ( 친구의 제안으로 개발 )","allTopics":[],"primaryLanguage":{"name":"Python","color":"#3572A5"},"pullRequestCount":0,"issueCount":0,"starsCount":0,"forksCount":1,"license":null,"participation":null,"lastUpdated":{"hasBeenPushedTo":true,"timestamp":"2024-07-15T22:21:59.565Z"}},{"type":"Public","name":"Faster-1-in-2-Probability-Executor-in-Node.js","owner":"Math-Engine","isFork":false,"description":"Faster - GitHub Actions를 사용하여 Node.js에서 1/2 확률을 계속해서 실행합니다.","allTopics":[],"primaryLanguage":{"name":"JavaScript","color":"#f1e05a"},"pullRequestCount":0,"issueCount":0,"starsCount":1,"forksCount":0,"license":null,"participation":null,"lastUpdated":{"hasBeenPushedTo":true,"timestamp":"2024-07-15T21:22:16.887Z"}},{"type":"Public","name":"PI-Test-1","owner":"Math-Engine","isFork":false,"description":"원주율의 소수점 아래 첫 번째 자리 수부터 n번째 자리 수까지의 합을 an으로 하는 수열의 규칙성을 찾습니다.","allTopics":[],"primaryLanguage":{"name":"JavaScript","color":"#f1e05a"},"pullRequestCount":0,"issueCount":0,"starsCount":0,"forksCount":0,"license":null,"participation":null,"lastUpdated":{"hasBeenPushedTo":true,"timestamp":"2024-02-08T08:18:49.231Z"}},{"type":"Public","name":"Job-Summary-Test-1-TestRun-1-Mystic-ov-26-with-Python","owner":"Math-Engine","isFork":true,"description":"Job Summary Test 1 - TestRun 1 - GitHub Actions를 사용하여 a^c - b^d = 2 를 만족하는 a, b, c, d 값을 찾습니다. ( 친구의 제안으로 개발 )","allTopics":[],"primaryLanguage":{"name":"Python","color":"#3572A5"},"pullRequestCount":0,"issueCount":0,"starsCount":0,"forksCount":1,"license":null,"participation":null,"lastUpdated":{"hasBeenPushedTo":true,"timestamp":"2024-01-13T08:10:33.565Z"}}],"repositoryCount":8,"userInfo":null,"searchable":true,"definitions":[],"typeFilters":[{"id":"all","text":"All"},{"id":"public","text":"Public"},{"id":"source","text":"Sources"},{"id":"fork","text":"Forks"},{"id":"archived","text":"Archived"},{"id":"template","text":"Templates"}],"compactMode":false},"title":"Math-Engine repositories"}