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+# Loading order problem
+
+## The problem
+
+There is a need for lazy components to know whether they are meant to be rendered sync or not, determined by server render.
+
+The case is this:
+
+Either of:
+
+1. Lazy component used multiple times, sometimes within a `Suspense` which gets rendered, sometimes within a `Suspense` which has fallback triggered
+2. Extraneous modules may be loaded as part of a chunk (i.e. chunks sometimes contain more modules than they need to)
+
+Then:
+
+```js
+const Lazy1Inner = Lazy(() =>
Lazy 1 inner
);
+const Lazy1 = Lazy(() => );
+const Lazy2 = Lazy(() => Lazy 2
);
+const Lazy3 = Lazy(() => Lazy 3
, {noSsr: true});
+
+const App = () => (
+
+ Loading...
}>
+
+
+ Loading...}>
+
+
+
+
+
+);
+```
+
+`Lazy3` is not server-rendered, so triggers fallback of 2nd Suspense. So what should happen on client is:
+
+As far as 2nd Suspense is concerned, none of `Lazy1`, `Lazy2`, `Lazy3` should be preloaded. But Lazy1 has been due to it's earlier usage.
+
+Calling order 2nd Suspense expects: `Lazy1`, `Lazy2`, `Lazy3`
+
+1. `Lazy1`
+2. `Lazy2`
+3. `Lazy3`
+(end of hydration)
+4. `Lazy1Inner`
+
+What actually happens is:
+
+1. `Lazy1`
+2. `Lazy1Inner`
+3. `Lazy2`
+4. `Lazy3`
+(end of hydration)
+
+If `Lazy()` implementation relies on calling order, it will not get what it expects.
+
+## Actually this is not a problem
+
+In the case of lazy component loading (as opposed to lazy *data* loading), order of calling is not important.
+
+The fallback will still get triggered on client, so the page will rehydrate correctly without errors.
+
+So it's fine for lazy component loading.
+
+## BUT could cause problems for other modules which do rely on calling order
+
+An implementation of lazy data loading might rely on calling order. In which case, this could be a problem.
+
+If `Lazy1Inner` was a lazy data fetcher, rather than lazy component fetcher, then it will get called in an unexpected order.
+
+Not good.