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use v6;
use Test;
# L<S06/Anonymous hashes vs blocks>
plan 18;
my $hash = {
'1' => { '2' => 3, '4' => 5 },
};
is( $hash<1><2>, '3', 'First nested element.');
is( $hash<1><4>, '5', 'Second nested element.');
my $h2 = {
x => [2,3]
};
is( $h2<x>[0], '2', 'First nested element.');
is( $h2<x>[1], '3', 'Second nested element.');
my %foo = (1 => 2);
my $bar = { %foo };
ok $bar ~~ Hash, '%foo in a block causes hash composing';
# pugs had problems with //= and the hash() contextualizer
{
my %hash;
%hash<foo> //= hash();
%hash<bar> //= hash;
my $h_ref;
$h_ref //= hash();
is(%hash<foo>.WHAT.gist, ::Hash.gist, "Parses as two items");
is(%hash<bar>.WHAT.gist, ::Hash.gist, "Parens do not help");
is($h_ref.WHAT.gist, ::Hash.gist, "It is not limited to hash values");
}
{
ok {; a => 1 } ~~ Block, '{; ... } is a Block';
ok { a => 1 } ~~ Hash, '{ a => 1} is a Hash';
#?pugs 4 skip "Missing required parameters"
ok { $^a => $^b } ~~ Block, 'placeholders force it to be a block';
ok { $^a => 'b' } ~~ Block, '... as a key';
ok { a => $^x } ~~ Block, '... as a value';
ok { b => 3, a => $^x, 4 => 5 } ~~ Block, '... somewhere deep inside';
ok {;} ~~ Block, '{;} is a Block';
}
#?niecza skip "Thinks the block is a hash"
{
my @foo = <a b>;
my %hash = map { (state $counter)++ => $_ }, @foo;
is %hash<0>, 'a', 'state variable declaration certainly makes it a block (1)';
is %hash<1>, 'b', 'state variable declaration certainly makes it a block (2)';
}
# RT #68298
is (map { $_ => $_ * $_ }, 1..3).hash<2>, 4, 'block with $_ is not a hash';
done;
# vim: ft=perl6
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