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use v6;
use Test;
=begin comment
This tests the &?ROUTINE magical value
=end comment
plan 6;
# L<S06/The C<&?ROUTINE> object>
# L<S02/Names/Which routine am I in>
sub factorial { @_[0] < 2 ?? 1 !! @_[0] * &?ROUTINE(@_[0] - 1) }
my $result1 = factorial(3);
is($result1, 6, 'the &?ROUTINE magical works correctly');
my $factorial = sub { @_[0] < 2 ?? 1 !! @_[0] * &?ROUTINE(@_[0] - 1) };
my $result2 = $factorial(3);
is($result2, 6, 'the &?ROUTINE magical works correctly in anon-subs');
sub postfix:<!!!> (Int $n) { $n < 2 ?? 1 !! $n * &?ROUTINE($n - 1) }
my $result3 = 3!!!;
is($result3, 6, 'the &?ROUTINE magical works correctly in overloaded operators' );
{
my $variable;
my regex foo { a { $variable = &?ROUTINE; } }
my token bar { b { $variable = &?ROUTINE; } }
my rule baz { c { $variable = &?ROUTINE; } }
"a" ~~ &foo;
is $variable, &foo, '&?ROUTINE is correct inside a regex';
"b" ~~ &bar;
is $variable, &bar, '&?ROUTINE is correct inside a token';
"c" ~~ &baz;
is $variable, &baz, '&?ROUTINE is correct inside a rule';
}
# vim: ft=perl6
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