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hash-interpolation.t
46 lines (37 loc) 路 1.09 KB
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hash-interpolation.t
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use v6;
use Test;
plan 12;
{
my %hash = (a => 1, b => 2, d => 4, c => 3);
is "%hash[]", "a\t1\nb\t2\nc\t3\nd\t4", '"%hash[]" works and sorts keys';
is "{%hash[]}", "a\t1\nb\t2\nc\t3\nd\t4", '"{%hash}" works and sorts keys';
}
{
my %hash = (a => 1, b => 2);
is "%hash<a>", 1, '"%hash<a>" works';
is "<%hash<a>>", '<1>', '"<%hash<a>>" works';
}
{
my $hash = { a => 1, b => 2 };
is "$hash<a>", 1, '"$hash<a>" works';
is "<$hash<a>>", '<1>', '"<$hash<a>>" works';
}
{
# L<S02/Arrays/In order to interpolate an entire hash>
my %hash = b => 2;
#?niecza 2 todo 'zen hash slice'
is "%hash{}", "b\t2", 'interpolation with curly braces';
is "%hash<>", "b\t2", 'interpolation with angle brackets';
is "%hash", '%hash', 'no interpolation';
}
{
# "%hash{a}" actually calls a(). Test that.
my %hash = (a => 1, b => 2);
sub do_a {
'b';
}
is "%hash{do_a}", "2", '%hash{do_a} calls do_a()';
is "%hash{'b'}", "2", 'can quote hash indexes in interpolations 1';
is "%hash{"b"}", "2", 'can quote hash indexes in interpolations 2';
}
# vim: ft=perl6