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// Simple grep. Only supports ^ . * $ operators.
#include "types.h"
#include "stat.h"
#include "user.h"
char buf[1024];
int match(char*, char*);
void
grep(char *pattern, int fd)
{
int n, m;
char *p, *q;
m = 0;
while((n = read(fd, buf+m, sizeof(buf)-m)) > 0){
m += n;
p = buf;
while((q = strchr(p, '\n')) != 0){
*q = 0;
if(match(pattern, p)){
*q = '\n';
write(1, p, q+1 - p);
}
p = q+1;
}
if(p == buf)
m = 0;
if(m > 0){
m -= p - buf;
memmove(buf, p, m);
}
}
}
int
main(int argc, char *argv[])
{
int fd, i;
char *pattern;
if(argc <= 1){
printf(2, "usage: grep pattern [file ...]\n");
exit();
}
pattern = argv[1];
if(argc <= 2){
grep(pattern, 0);
exit();
}
for(i = 2; i < argc; i++){
if((fd = open(argv[i], 0)) < 0){
printf(1, "grep: cannot open %s\n", argv[i]);
exit();
}
grep(pattern, fd);
close(fd);
}
exit();
}
// Regexp matcher from Kernighan & Pike,
// The Practice of Programming, Chapter 9.
int matchhere(char*, char*);
int matchstar(int, char*, char*);
int
match(char *re, char *text)
{
if(re[0] == '^')
return matchhere(re+1, text);
do{ // must look at empty string
if(matchhere(re, text))
return 1;
}while(*text++ != '\0');
return 0;
}
// matchhere: search for re at beginning of text
int matchhere(char *re, char *text)
{
if(re[0] == '\0')
return 1;
if(re[1] == '*')
return matchstar(re[0], re+2, text);
if(re[0] == '$' && re[1] == '\0')
return *text == '\0';
if(*text!='\0' && (re[0]=='.' || re[0]==*text))
return matchhere(re+1, text+1);
return 0;
}
// matchstar: search for c*re at beginning of text
int matchstar(int c, char *re, char *text)
{
do{ // a * matches zero or more instances
if(matchhere(re, text))
return 1;
}while(*text!='\0' && (*text++==c || c=='.'));
return 0;
}
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