diff --git a/Challenge/lbu0413/everyArray/README.md b/Challenge/lbu0413/everyArray/README.md
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+++ b/Challenge/lbu0413/everyArray/README.md
@@ -0,0 +1,9 @@
+# 문제제목
+
+## 설명
+
+every를 이용해서 모든 원소가 짝수인지 아닌지를 판별하세요
+
+## Expected Output 
+
+true
\ No newline at end of file
diff --git a/Challenge/lbu0413/everyArray/solve.js b/Challenge/lbu0413/everyArray/solve.js
new file mode 100644
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+++ b/Challenge/lbu0413/everyArray/solve.js
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+function solution(inputArray) {
+  return inputArray.every((i) => i % 2 === 0);
+}
+
+const inputArray = [2, 4, 6, 8, 10];
+
+// const inputArray2 = [2, 3, 6, 8, 10];
+// console.log(solution(inputArray2));
+// exports.solution = solution;
diff --git a/Challenge/lbu0413/everyArray/solve.test.js b/Challenge/lbu0413/everyArray/solve.test.js
new file mode 100644
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+++ b/Challenge/lbu0413/everyArray/solve.test.js
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+const { solution } = require("./solve");
+
+const test1 = {
+  input: [2, 4, 6, 8, 10],
+  answer: true,
+};
+
+const test2 = {
+  input: [2, 3, 6, 8, 10],
+  answer: false,
+};
+
+describe("everyArray", () => {
+  test("모두 짝수면 true여야 한다.", () => {
+    expect(solution(test1.input)).toEqual(test1.answer);
+  });
+
+  test("홀수가 있으면 false여야 한다.", () => {
+    expect(solution(test2.input)).toEqual(test2.answer);
+  });
+});
diff --git a/Challenge/lbu0413/expDivOdd/README.md b/Challenge/lbu0413/expDivOdd/README.md
new file mode 100644
index 00000000..c07ab10b
--- /dev/null
+++ b/Challenge/lbu0413/expDivOdd/README.md
@@ -0,0 +1,3 @@
+## 설명
+
+제곱한 후 3으로 나눈 나머지가 홀수인 것 을 뽑은 배열의 총 합을 구하세요.
diff --git a/Challenge/lbu0413/expDivOdd/solve.js b/Challenge/lbu0413/expDivOdd/solve.js
new file mode 100644
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+++ b/Challenge/lbu0413/expDivOdd/solve.js
@@ -0,0 +1,11 @@
+// ## 설명
+
+// 제곱한 후 3으로 나눈 나머지가 홀수인 것 을 뽑은 배열의 총 합을 구하세요.
+
+function solution(inputArray) {
+  return inputArray
+    .map((i) => i * i)
+    .filter((i) => i % 3 === 1)
+    .reduce((acc, i) => acc + i);
+}
+exports.solution = solution;
diff --git a/Challenge/lbu0413/expDivOdd/solve.test.js b/Challenge/lbu0413/expDivOdd/solve.test.js
new file mode 100644
index 00000000..ca37fcc3
--- /dev/null
+++ b/Challenge/lbu0413/expDivOdd/solve.test.js
@@ -0,0 +1,21 @@
+const { solution } = require('./solve');
+
+const test1 = {
+  input: [1, 7, 3, 4, 6],
+  answer: 66,
+};
+
+const test2 = {
+  input: [2, 3, 6, 8, 10],
+  answer: 168,
+};
+
+describe('everyArray', () => {
+  test('1, 7, 3, 4, 6', () => {
+    expect(solution(test1.input)).toEqual(test1.answer);
+  });
+
+  test('2, 3, 6, 8, 10', () => {
+    expect(solution(test2.input)).toEqual(test2.answer);
+  });
+});
diff --git a/Challenge/lbu0413/filterAge/README.md b/Challenge/lbu0413/filterAge/README.md
new file mode 100644
index 00000000..873a15c1
--- /dev/null
+++ b/Challenge/lbu0413/filterAge/README.md
@@ -0,0 +1,3 @@
+## 설명
+
+배열 원소의 age가 30이상 50미만인 사람만 있는 객체의 배열을 만드세요
diff --git a/Challenge/lbu0413/filterAge/solve.js b/Challenge/lbu0413/filterAge/solve.js
new file mode 100644
index 00000000..9dcb1815
--- /dev/null
+++ b/Challenge/lbu0413/filterAge/solve.js
@@ -0,0 +1,24 @@
+// write your codes
+// const input = [
+//   {
+//     name: "영미",
+//     age: 25,
+//   },
+//   {
+//     name: "일미",
+//     age: 35,
+//   },
+//   {
+//     name: "이미",
+//     age: 45,
+//   },
+//   {
+//     name: "삼미",
+//     age: 55,
+//   },
+// ];
+function solution(inputArray) {
+  return inputArray.filter((i) => i.age >= 30 && i.age < 50);
+}
+
+exports.solution = solution;
diff --git a/Challenge/lbu0413/filterAge/solve.test.js b/Challenge/lbu0413/filterAge/solve.test.js
new file mode 100644
index 00000000..b9081601
--- /dev/null
+++ b/Challenge/lbu0413/filterAge/solve.test.js
@@ -0,0 +1,32 @@
+const { solution } = require('./solve');
+
+const test1 = {
+  input: [
+    {
+      name: '영미',
+      age: 25,
+    },
+    {
+      name: '일미',
+      age: 35,
+    },
+    {
+      name: '이미',
+      age: 45,
+    },
+    {
+      name: '삼미',
+      age: 55,
+    },
+  ],
+  answer: [
+    { name: '일미', age: 35 },
+    { name: '이미', age: 45 },
+  ],
+};
+
+describe('filterAge', () => {
+  test('test1', () => {
+    expect(solution(test1.input)).toEqual(test1.answer);
+  });
+});
diff --git a/Challenge/lbu0413/filterIntersection/README.md b/Challenge/lbu0413/filterIntersection/README.md
new file mode 100644
index 00000000..d7c9ad39
--- /dev/null
+++ b/Challenge/lbu0413/filterIntersection/README.md
@@ -0,0 +1,5 @@
+# 문제제목
+
+## 설명
+
+두 배열의 교집합을 출력하세요!
diff --git a/Challenge/lbu0413/filterIntersection/solve.js b/Challenge/lbu0413/filterIntersection/solve.js
new file mode 100644
index 00000000..b9828d87
--- /dev/null
+++ b/Challenge/lbu0413/filterIntersection/solve.js
@@ -0,0 +1,8 @@
+// const A = [1, 2, 3, 4, 5];
+// const B = [3, 4, 5, 6, 7];
+
+function solution(inputArray1, inputArray2) {
+  return inputArray1.filter((i) => inputArray2.includes(i));
+}
+
+exports.solution = solution;
diff --git a/Challenge/lbu0413/filterIntersection/solve.test.js b/Challenge/lbu0413/filterIntersection/solve.test.js
new file mode 100644
index 00000000..576cbc86
--- /dev/null
+++ b/Challenge/lbu0413/filterIntersection/solve.test.js
@@ -0,0 +1,15 @@
+const { solution } = require('./solve');
+
+const test1 = {
+  input: {
+    A: [1, 2, 3, 4, 5],
+    B: [3, 4, 5, 6, 7],
+  },
+  answer: [3, 4, 5],
+};
+
+describe('filterIntersection', () => {
+  test('test1', () => {
+    expect(solution(test1.input.A, test1.input.B)).toEqual(test1.answer);
+  });
+});