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Add refined return type for context #9

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mielientiev commented Feb 28, 2017

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Show outdated Hide outdated core/src/main/scala/contextual/prefix.scala
@@ -35,8 +35,9 @@ object Prefix {
* @return a new instance of a [[Prefix]]
*/
def apply(interpolator: Interpolator, stringContext: StringContext):
Prefix[interpolator.ContextType, interpolator.type] =
Prefix[interpolator.type#Output, interpolator.ContextType, interpolator.type] =

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@propensive

propensive Feb 28, 2017

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Can we write interpolator.Output instead of interpolator.type#Output? I think they should be identical.

@propensive

propensive Feb 28, 2017

Owner

Can we write interpolator.Output instead of interpolator.type#Output? I think they should be identical.

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@mielientiev
@mielientiev

@propensive propensive referenced this pull request May 3, 2017

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Error in example? #16

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