Large layouts do not display

[vascotenner]

A larger layout is not displayed when created with hv.Layout.

Works:

a[0]+a[1]+a[2]+a[3]

Does not work:

hv.Layout(a)

But returns

:Layout
   .Overlay.Beam     :Overlay
      .Image.Beam :Image   [x,y]   (z)
      .Level.Beam :Overlay
         .Beam :NdOverlay   [Levels]
            :Contours   [x,y]   (z)
   .Diff.Differences :Image   [x,y]   (z)
   .Table.I          :Table   [Name]   (radius,error)
   .Overlay.I        :Overlay
      .Curve.I  :Curve   [y]   (z)
      .Curve.II :Curve   [y]   (z)

Current solution:

hv.Layout(a).display('all')

Proposition

always display large layouts

[jbednar]

Is there instead an option that determines how large a layout can be and still be displayed, which could be set to infinity by a user that always wants to see large layouts? That said, four items doesn't sound like a large layout.

[vascotenner]

It should at least give a warning that it does not display because it is to large + explanation how to show it.

Furthermore, the behaviour of +, Layout, hmap.layout should be identical.

[jbednar]

I agree on all counts!

[jlstevens]

I also agree.

I think issuing a warning and ensuring consistent behavior regardless of how the Layout is constructed is something we could fix for 1.7.

[philippjfr]

I say we throw out the max_branches option on the OutputMagic, then there's only one limit to worry about which is max_frames, which is far easier to reason about. We could consider adding a max subplots option instead but I think that should have nothing to do with a Layout in particular. Therefore my preference would be to put a deprecation warning in Layout.display and then remove the conditional in the layout_display hook. It would just be something like this:

if isinstance(layout, Layout) and len(layout.data) * nframes > max_frames:
       max_frame_warning(max_frames)
       return '<tt>'+ sanitize_HTML(layout) + '</tt>'

[philippjfr]

Now implemented, we no longer check the number of branches on the Layout now and the Layout.display function is deprecated.