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[processing] Fix hasGeometry() method when output is a geometry-less vector table
From the dox for QgsProcessing.TypeVector: "When used for a sink this indicates
the sink has no geometry.". If an algorithm is using this value to indicate
"maybe has geometry" for an output, then that algorithm is incorrect and
should be using TypeVectorAnyGeometry instead.
(cherry picked from commit 583b602)
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