diff --git a/Section1.drawio.png b/Section1.drawio.png new file mode 100644 index 000000000..a41eba59a Binary files /dev/null and b/Section1.drawio.png differ diff --git a/assignment1.sql b/assignment1.sql new file mode 100644 index 000000000..f1c4d3629 --- /dev/null +++ b/assignment1.sql @@ -0,0 +1,211 @@ + /* ASSIGNMENT 1 */ +--Please write responses between the QUERY # and END QUERY blocks +/* SECTION 2 */ + + +--SELECT +/* 1. Write a query that returns everything in the customer table. */ +--QUERY 1 +SELECT * +FROM customer; + + + +--END QUERY + + +/* 2. Write a query that displays all of the columns and 10 rows from the customer table, +sorted by customer_last_name, then customer_first_ name. */ +--QUERY 2 +SELECT * +FROM customer +ORDER BY customer_last_name, customer_first_name +LIMIT 10; + + +--END QUERY + + +--WHERE +/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. +Limit to 25 rows of output. */ +--QUERY 3 +SELECT * +FROM customer_purchases +WHERE product_id = 4 or product_id = 9 +LIMIT 25; + + + +--END QUERY + + + +/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), +filtered by customer IDs between 8 and 10 (inclusive) using either: + 1. two conditions using AND + 2. one condition using BETWEEN +Limit to 25 rows of output. +*/ +--QUERY 4 +SELECT * +,quantity * cost_to_customer_per_qty as price +FROM customer_purchases +WHERE customer_id BETWEEN 8 and 10 +LIMIT 25; + + +--END QUERY + + +--CASE +/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. +Using the product table, write a query that outputs the product_id and product_name +columns and add a column called prod_qty_type_condensed that displays the word “unit” +if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */ +--QUERY 5 +SELECT product_id, product_name +,CASE WHEN product_qty_type = 'unit' THEN 'unit' + ELSE 'bulk' + END as prod_qty_type_condensed +FROM product; + + + +--END QUERY + + +/* 2. We want to flag all of the different types of pepper products that are sold at the market. +add a column to the previous query called pepper_flag that outputs a 1 if the product_name +contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */ +--QUERY 6 +SELECT product_id, product_name +,CASE WHEN product_qty_type = 'unit' THEN 'unit' + ELSE 'bulk' + END as prod_qty_type_condensed +,CASE WHEN product_name LIKE '%pepper%' + THEN 1 + ELSE 0 + END as pepper_flag +FROM product; + + + +--END QUERY + + +--JOIN +/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the +vendor_id field they both have in common, and sorts the result by market_date, then vendor_name. +Limit to 24 rows of output. */ +--QUERY 7 +SELECT vendor.vendor_id + FROM vendor + INNER JOIN vendor_booth_assignments + ON vendor.vendor_id = vendor_booth_assignments.vendor_id +ORDER BY market_date, vendor_name +LIMIT 24; + + +--END QUERY + + + +/* SECTION 3 */ + +-- AGGREGATE +/* 1. Write a query that determines how many times each vendor has rented a booth +at the farmer’s market by counting the vendor booth assignments per vendor_id. */ +--QUERY 8 +SELECT vendor_id, +COUNT(*) +FROM vendor_booth_assignments +GROUP BY vendor_id; + + + +--END QUERY + + +/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper +sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list +of customers for them to give stickers to, sorted by last name, then first name. + +HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */ +--QUERY 9 +SELECT customer.customer_id, + customer.customer_last_name, + customer.customer_first_name +FROM customer + INNER JOIN customer_purchases + ON customer.customer_id = customer_purchases.customer_id +GROUP BY customer.customer_id, + customer.customer_first_name, + customer.customer_last_name +HAVING SUM(quantity * cost_to_customer_per_qty) > 2000 +ORDER BY customer.customer_last_name, customer.customer_first_name; + + + +--END QUERY + + +--Temp Table +/* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: +Thomass Superfood Store, a Fresh Focused store, owned by Thomas Rosenthal + +HINT: This is two total queries -- first create the table from the original, then insert the new 10th vendor. +When inserting the new vendor, you need to appropriately align the columns to be inserted +(there are five columns to be inserted, I've given you the details, but not the syntax) + +-> To insert the new row use VALUES, specifying the value you want for each column: +VALUES(col1,col2,col3,col4,col5) +*/ +--QUERY 10 +DROP TABLE IF EXISTS temp.new_vendor; + +CREATE TABLE temp.new_vendor as + SELECT * + FROM vendor; + +INSERT INTO temp.new_vendor + VALUES(10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal'); + + +--END QUERY + + +-- Date +/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table. + +HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month +and year are! +Limit to 25 rows of output. */ +--QUERY 11 +SELECT customer_id, + strftime('%m', market_date) as month, + strftime('%Y', market_date) as year +FROM customer_purchases +LIMIT 25; + + + +--END QUERY + + +/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. +Remember that money spent is quantity*cost_to_customer_per_qty. + +HINTS: you will need to AGGREGATE, GROUP BY, and filter... +but remember, STRFTIME returns a STRING for your WHERE statement... +AND be sure you remove the LIMIT from the previous query before aggregating!! */ +--QUERY 12 +SELECT customer_id, + SUM(quantity * cost_to_customer_per_qty) +FROM customer_purchases +WHERE strftime('%m', market_date) = '04' AND strftime('%Y', market_date) = '2022' +GROUP BY customer_id + +-- THIS WAS HARD, TOOK ME FOEVER + +--END QUERY