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# The MIT License
#
# All contents Copyright (c) 2004-2008 Reginald Braithwaite
# <http://braythwayt.com> except as otherwise noted.
#
# Permission is hereby granted, free of charge, to any person obtaining a copy
# of this software and associated documentation files (the "Software"), to deal
# in the Software without restriction, including without limitation the rights
# to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
# copies of the Software, and to permit persons to whom the Software is
# furnished to do so, subject to the following conditions:
#
# The above Copyright notice and this permission notice shall be included in
# all copies or substantial portions of the Software.
#
# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
# IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
# FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
# AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
# LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
# OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
# THE SOFTWARE.
#
# http://www.opensource.org/licenses/mit-license.php
def divide_and_conquer(value, steps)
if steps[:divisible?].call(value)
steps[:recombine].call(
steps[:divide].call(value).map { |sub_value| divide_and_conquer(sub_value, steps) }
)
else
steps[:conquer].call(value)
end
end
def linear_recursion(value, steps)
if steps[:divisible?].call(value)
trivial_part, sub_problem = steps[:divide].call(value)
steps[:recombine].call(
trivial_part, linear_recursion(sub_problem, steps)
)
else
steps[:conquer].call(value)
end
end
alias :multirec :divide_and_conquer
alias :linrec :linear_recursion
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