A wrapper for a remote SPARQL endpoint
Python Other
Latest commit c91cdc8 Feb 14, 2017 @dayures dayures Added some documentation about the parameter to indicate the output f…
…ormat. Maybe useful for #82

README.md

SPARQL Endpoint interface to Python

Build Status PyPi version

SPARQLWrapper is a simple Python wrapper around a SPARQL service to remotelly execute your queries. It helps in creating the query invokation and, possibly, convert the result into a more manageable format.

Installation

From PyPi:

$ pip install sparqlwrapper

From GitHub::

$ pip install git+https://github.com/rdflib/sparqlwrapper#egg=sparqlwrapper

From Debian

$ sudo apt-get install python-sparqlwrapper

Usage

Create an instance to execute your query:

from SPARQLWrapper import SPARQLWrapper, JSON

sparql = SPARQLWrapper("http://dbpedia.org/sparql")
sparql.setQuery("""
    PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
    SELECT ?label
    WHERE { <http://dbpedia.org/resource/Asturias> rdfs:label ?label }
""")
sparql.setReturnFormat(JSON)
results = sparql.query().convert()

for result in results["results"]["bindings"]:
    print(result["label"]["value"])

Source code

The source distribution contains:

  • SPARQLWrapper: the Python library. You should copy the directory somewhere into your PYTHONPATH. Alternatively, you can also run the distutils scripts:

    python setup.py install

  • test: some unit and integrations tests

  • script: some scripts to run the library against some SPARQL endpoints.

License

The package is licensed under W3C license.