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implement higher-order unification for type constructor inference #2712

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@scabug

implement what's described in "Partial polymorphic type inference and higher-order unification"

object Test {
  def meh[M[_], A](x: M[A]): M[A] = x
  meh{(x: Int) => x} // should solve ?M = [X] X => X and ?A = Int ... 
}

Activity

  1. scabug commented on Nov 27, 2009

    @scabug
    Author

    Imported From: https://issues.scala-lang.org/browse/SI-2712?orig=1
    Reporter: @adriaanm
    Other Milestones: 2.12.0-M5
    See #4719
    Blocks #5993

  2. scabug commented on Jun 4, 2011

    @scabug
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    Harrison Klaperman (hlklaperman) said:
    You can find that paper here: http://www.cs.cmu.edu/~fp/papers/lfp88.pdf. I hope this is useful to others who stumble upon this issue. Now if only I understood what the paper were talking about...

  3. scabug commented on Oct 19, 2011

    @scabug
    Author

    @Blaisorblade said:
    Further work on that problem is described in "Unification via explicit substitutions: The case of higher-order patterns" - http://www.cs.cmu.edu/~fp/papers/INRIA-RR-3591.pdf, from Dowek, Hardin, Kirchner and Pfenning (Pfenning is the author of the above paper). I am not an expert, but this work is cited in Pierce's TAPL (Sec. 23.6, pag. 355), which explains that unlike the algorithm above it is terminating and always finds a unique solution; the paper suggests that this work applies to an important subcase. However, I cannot fully judge myself the respective merits of the two papers.

  4. scabug commented on Nov 6, 2011

    @scabug
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    @milessabin said:
    With dependent method types we have a somewhat cumbersome, but just about usable workaround. The key idea is to use implicits to destructure a type, and then pick out and use its component parts as dependent types.

    // Template we will unpack into
    trait UnpackM[MA] {
      type M[_]
      type A
    }
      
    // Destructuring implicits
    implicit def unpackM1[M0[_], A0] = new UnpackM[M0[A0]] {
      type M[X] = M0[X]
      type A = A0
    }
    
    implicit def unpackM2[M0[_, _], A0, B0] = new UnpackM[M0[A0, B0]] {
      type M[X] = M0[A0, X]
      type A = B0
    }
    
    def meh[MA](x : MA)(implicit u : UnpackM[MA]) : (u.M[String], List[u.A]) = null
    //      ^^          ^^^^^^^^^^^^^^^^^^^^^^^^     ^^^^^^^^^^^       ^^^
    //      (1)                   (2)                    (3)           (3)
    // 1: Type variable being destructured
    // 2: Destructuring implicit
    // 3: Uses of (dependent) component types
      
    val m = meh{(x: Int) => x}
    implicitly[m.type <:< (Int => String, List[Int])]

    See also here for a slightly more elaborate scalaz inspired example.

  5. scabug commented on Dec 9, 2011

    @scabug
    Author

    @Blaisorblade said:
    Milles Sabin, your workaround is interesting:
    But unfortunately the example you link still needs these two lines:

    type EitherInt[A] = Either[Int, A]
    implicit object EitherTC extends TC[EitherInt]

    Moreover, your code does not even correctly solve the original problem - it only infers that Int => Int matches M0[A0, B0] with M0 = Function1, not that it matches M1[A1] with M1[X] = X => X.

  6. scabug commented on Dec 2, 2012

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    @retronym said:
    See also #6744, where we would like to infer these sort of types in pattern matching.

  7. scabug commented on Dec 2, 2012

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    @pchiusano said:
    Would it be any easier to just look for partial applications of existing type constructors in left-to-right order? Haskell does roughly this (actually, type constructors are just curried, see below), it is tractable, and people don't seem to have an issue with the limitation, though occasionally you do have to introduce a new type just to flip the order of some type parameters.

    Here's an example:

    case class State[S,A](run: S => (A,S))
    object Blah {
      def foo[M[_],A](m: M[A]): M[A] = m
      ...
      val blah = foo(State((i: Int) => ("hi",i+1)))
    }

    Another way to think about this is that type constructors are curried, so State[S,A] is actually represented as Ap(Ap(State, S), A), and likewise the M[A] is Ap(freevar, A) - these unify with freevar = Ap(State, S).

  8. scabug commented on Apr 19, 2013

    @scabug
    Author

    Dan Rosen (mergeconflict) said:
    To Paul's comment, I agree that looking at the type parameters as curried, partially applied from left to right (#4719) is probably usually good enough.

    If State[S, A] has pseudo-Haskell-ish kind (*, *) -> *, then State[S][A] would have kind * -> * -> *, and State[S] would have kind * -> *.

  9. scabug commented on Sep 17, 2014

    @scabug
    Author

    @Blaisorblade said:
    It seems somehow I never mentioned higher-order pattern unification by Miller, which is what Agda uses — the paper I linked ("Unification via explicit substitutions: The case of higher-order patterns") is indeed about that. For whatever reason, everybody steers away from the original Huet algorithm, including modern implementation of lambdaProlog (which is what "Partial Polymorphic Type Inference and Higher-Order Unification" uses).

  10. scabug commented on Jun 30, 2015

    @scabug
    Author

    @adriaanm said:
    Oh, jira.

  11. scabug commented on Jun 30, 2015

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    Author

    @SethTisue said:
    #2712 closed!! Dewey defeats Truman!!

  12. scabug commented on Jun 30, 2015

    @scabug
    Author

    @milessabin said:
    That was cruel and heartless ...

  13. scabug commented on Jun 30, 2015

    @scabug
    Author

    @etorreborre said:
    My heart rate went up for a moment...

  14. scabug commented on Jun 30, 2015

    @scabug
    Author

    Stephen Compall (s11001001) said:
    long, wistful sigh

  15. scabug commented on Jul 1, 2015

    @scabug
    Author

    Jed Wesley-Smith (jedws) said:
    well, that was (briefly) exciting!

  16. scabug commented on Jul 23, 2015

    @scabug
    Author

    Matthew Pocock (drdozer) said:
    I keep on hitting this issue in various forms, most recently when trying to use type lambdas to fill in one of two types on a * -> * -> * kinded type. I have this type:

    case class RangeAs[R, V](range: R, lower: V, upper: V)
    
    object RangeAs {
      trait Aux[V] {
        type l[R] = RangeAs[R, V]
      }
    }
    

    There are various implicit instances with RangeAs.Aux[X]#l as one of their type parameters. They are not found in all situations if I attempt to summon them using the lambda. However, if I do this:

    type RangeAsX[T] = RangeAs.Aux[X]#l[T]
    

    Now if I summon them using RangeAsX, they are found.

  17. scabug commented on Apr 12, 2016

    @scabug
    Author

    @ijuma said:
    For the watchers of this JIRA that haven't seen this on Twitter, Miles posted a demo project exercising a proposed fix for this JIRA:

    https://github.com/milessabin/si2712fix-demo

  18. scabug commented on Apr 15, 2016

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    Author

    @milessabin said:
    PR against 2.12.x here: scala/scala#5102.

  19. scabug commented on Aug 26, 2016

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    Author

    @milessabin said:
    Backport to 2.11.8 available here.

  20. scabug commented on Oct 18, 2016

    @scabug
    Author

    @adriaanm said:
    2.11.9 PR: scala/scala#5343

  21. added this to the milestone on Apr 7, 2017
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