Non-zero exit code on syntax error

[lassik]

What version of standard?

11.0.1

What operating system, Node.js, and npm version?

MacOS, Node.js 10.6.0, npm 6.1.0

What did you expect to happen?

I expected this shell command:

echo "(" | standard; echo "exit code is $?"

to say that the exit code is some number other than zero (because zero conventionally means success, whereas non-zero means failure). I believe it would be appropriate so that editor plugins and batch jobs don't try to use the output from stdout as if it were valid code.

What actually happened?

The exit code is zero (indicating success) even when there is a syntax error in the input.

[lassik]

Sorry, my mistake. I neglected to use the --stdin flag so instead it tried to format a .js file that I happened to have in the current directory.

This works fine:

$ echo "(" | standard --stdin; echo "exit code is $?"
...
exit code is 1

and also with the --fix option:

$ echo "(" | standard --stdin --fix; echo "exit code is $?"
...
exit code is 1